**A function f(x) is defined as f(x) = f(x - 2) - x(x + 2) for all the integer values of x and f(1) + f(4) = 0. What is the value of f(1) + f(2) + f(3) + f(4) + f(5) + f(6)?**- 0
- 89
- -89
- None of these

Answer: Option C

Let S = f(1) + f(2) + f(3) + f(4) + f(5) + f(6)

As f(1) + f(4) = 0, therefore S = f(2) + f(3) + f(5) + f(6) ------ (1)

f(2) = f(0) - 8

f(3) = f(1) - 15

f(4) = f(2) - 24 = f(0) - 32

f(5) = f(3) - 35 = f(1) - 50

f(6) = f(4) - 48 = f(0) - 80

Put the above values in equation (1), we get

S = f(0) - 8 + f(1) - 15 + f(1) - 50 + f(0) - 80

S = 2(f(0) + f(1)) - 153 ------ (2)

As we already know f(1) + f(4) = 0 ⇒f(1) + f(0) - 32 = 0 ⇒f(1) + f(0) = 32

Putting this value in equation 2, we get S = 2(32) - 153 = -89

So, Ans is option C.

**In ΔABC, the internal bisectors of ∠ABC and ∠ACB met at I and ∠BAC = 50°. The measure of ∠BIC is**- 105°
- 115°
- 125°
- 130°

Answer: Option B

I is the In-centre

So, ∠BIC = 90° + 1/2 ∠BAC

= 90° + 1/2 × 50 = 115°**The difference between [3/5] of [2/3] a number and [2/5] of[1/4] of the same number is 288. What is the number?**- 960
- 850
- 895
- 955

Answer: Option A

Let the no. Be [3/5] x [{2/3}x]-[2/5] x [1/4]x,then = 288 Solving it we will get 960

**A, B, C and D are four consecutive odd numbers and their average is 42. What is the product of B and D?**- 1860
- 1890
- 1845
- 1677
- None of these

Answer: Option C

As diff. Is same so average should lie between B and C so B is 41 & C is 43 so D must be 45 as we have to find the product of B and D so it would be 1845**The cost price of item A, Item A was sold at a profit of 10% and Item B was sold at a loss of 20%. If the respective ratio of selling price of items A and B is 11:12, what is the cost price of item B?**- Rs.450/-
- Rs.420/-
- Rs.400/-
- Rs.350/-
- Rs.480/-

Answer: Option A

The cost price of item B is Rs. 150/- more than the Let us assume cost price of A= X

So that Cost price of B= X+150.

SP of A= X*1.1

SP of B=(X+150)*0.8

Given that

SPA: SPB

11:12

So that 1.1X/(X+150)*0.8= 11/12

X=300

CP of B= 300+150=450

Answer is 450.

Amazon Preparation Links

- Sample Aptitude Questions of Amazon
- Careers in Amazon
- All About Amazon
- Free Mock Amazon Placement Paper
- Join free prep course for Amazon
- Test Pattern & Selection Procedure of Amazon

**A sum of Rs 731 is divided among A, B and C such that 'A' receive 25% more than 'B' and 'B' receive 25% less than 'C'. What is C's share in the amount?**- Rs. 172
- Rs. 200
- Rs. 262
- Rs. 258
- None of these

Answer: Option E

A + B + C = 731 ..... (i)

A = 1.25B, gives A = 1.25 * 0.75 C = 0.9375 C....(ii)

B = 0.75C....(iii)

Using (ii) and (iii) in (i) we get

0.9375C + 0.75C + C = 731, gives C = 272.

So option E is the answer.**In how many different ways can letters of the word "PRAISE" be arranged?**- 720
- 610
- 360
- 210
- None of these

Answer: Option A

As total number of alphabets in PRAISE are 6, so total no. of ways is 6!=720 So option A is the answer**If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 300%, the resultant fraction is [5/18]. What is original fraction?**- 4/9
- 4/5
- 8/9
- 8/11
- None of these

Answer: Option A

Let the fraction be [n/d] & after that it becomes [2.5n/4d]=5/18 . So we get the result as [4/9]**A car covers the first 30 km of its journey in 45 minutes and the remaining 25 km in 30 minutes. What is the average speed of the car?**- 60
- 64
- 49
- 48
- None of these

Answer: Option E

Total distance/Total time =(30+25)/[(3/4)+(1/2)]

Average Speed=44kmph**Four examiners can examine a certain number of answer papers in 10 days by working for 5 hours a day. For how many hours a day would 2 examiners have to work in order to examine twice the number of answer papers in 20 days?**- 8
- 7.5
- 10
- 8.5
- None of The above

Answer: Option CExaminers Days Hours/Day Papers 4 10 5 x 2 20 ? 2x

Using chain rule,

(4×10×5)/X= (2×20×Y)/2X

X=10 hrs/day