**Dharma invested Rs. P for 3 years in scheme A which offered 12% p.a. simple interest. She also invested Rs. P + 400 in scheme B which offered 10% compound interest (compounded annually), for 2 years. If the amount received from scheme A was less than that received from scheme B, by Rs. 304, what is the value of P?**- Rs. 1400
- Rs. 1000
- Rs. 1500
- Rs. 900
- Rs. 1200

Answer: : Option E

As given, P + 3*12*P/100 + 304 = (P+400)(1+11/100)2

P(0.15)= 180;

P= 1200**Shiva gives 20% of her monthly salary to his mother, 50% of the remaining salary he invests in an insurance scheme and PPF in the respective ratio of 5 : 3 and the remaining he keeps in his bank account. If the sum of the amount he gives to his mother and that he invests in PPF is Rs. 12,600, how much is Shiva’s monthly salary?**- Rs. 36,000
- Rs. 64,000
- Rs. 42,000
- Rs. 40,000
- None of these

Answer: Option A

Let the total amount be x.

0.2x = given to mother.

0.25x= invested in insurance

0.15x= invested in ppf

0.4x= Bank account

Given, 0.2x+0.15x = 0.35x = 12600; x=36000**The respective ratio of radii of two right circular cylinders (A & B) is 4 : 7. The respective ratio of the heights of cylinders A and B is 2 : 1. What is the respective ratio of volumes of cylinders A and B?**- 25 :42
- 23 : 42
- 32 : 49
- 30 : 49
- 36 : 49

Answer: Option C.

V^{A}:V^{B}= πr^{A}_{2}h^{A}: πr_{B}^{2}h_{B}

= 4^{2}x2 : 7_{2}x1 = 32:49**If****(x – 3)**^{2}+ (y – 5)^{2}+ (z – 4)^{2}= 0**, then the value of****x**^{2}/9 + y^{2}/25 + z^{2}/16**is**- 12
- 9
- 3
- 1

Answer: Option C.

(x – 3)^{2}+ (y – 5)^{2}+ (z – 4)^{2}= 0

⇒ x – 3 = 0 ⇒ x= 3

Y – 5 = 0 ⇒ y = 5

Z – 4 = 0 ⇒ z = 4

**If 4x/3 + 2P = 12 for what value of P, x = 6?**- 6
- 4
- 2
- 1

Answer: Option C.

When x = 6, (4 * 6)/3 + 2P = 12

⇒ 8 + 2P = 12

⇒ 2P = 12 – 8 = 4

⇒ P = 2CommScope Preparation Links- Sample Aptitude Questions of CommScope
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**In ΔABC, ∠A + ∠B = 65°, ∠B + ∠C = 140°, then find ∠B.**- 40°
- 25°
- 35°
- 20°

Answer: Option B.

∠A + ∠B = 65°

∴ ∠C = 180° - 65° = 115°

∠B + ∠C = 140°

∴ ∠B = 140° - 115° = 25°**There are two motor cycles (A & B) of equal cost price. Motorcycle A was sold at a profit of 14% and motorcycle B was sold for Rs. 4,290/- more than its cost price. The net profit earned after selling both the motor cycles (A & B) is 20%. What is the cost price of each motorcycle?**- Rs. 16,500/-
- Rs. 16,000/-
- Rs. 15,500/-
- Rs. 71,500/-
- Rs. 17,000/-

Answer: Option A.

Let the cost price of each motorcycle be Rs. ‘A’. So SP of A = 1.14A and SP of B = A + 4290. Total CP = 2A. As net profit is given to be 20% on both the motorcycles, so we can form the equation as (2.14A + 4290 - 2A)/2A = 20%. Solving it further, we get (0.14A + 4290)5 = 2A. Solving this equation, we get value of A as 16,500. Hence answer is option A**Raman invested Rs. P for 2 years in scheme A which offered 20% p.a. compound interest (compounded annually). He lent the interest earned from scheme A to Shubh, at the rate of 7.5% p.a. simple. If at the end of 2 years, Shubh gave Rs. 3036 to Raman and thereby repaid the whole amount(actual loan + interest), what is the value of P?**- Rs. 6000
- Rs. 5800
- Rs. 6800
- Rs. 5400
- Rs. 6400

Answer: Option A.

P*(1.2)2 = 1.44P

Interest = P – 1.44P = 0.44P

0.44P + (0.44P * 7.5 * 2)/100 = 3036

Solving, we get P = 6000.**Three persons work independently on a problem. If the respective probabilities that they will solve it are 1/3, 1/4 and 1/5, then the probability that none can solve it is**- 1/5
- 1/3
- 2/5
- None of these

Answer: Option C.

Joint probability of all not being able to solve it is

**A person standing on the bank of a river observes that the angle of elevation of the top of a tree on the opposite bank of the river is 60° and when he retires 40 metres away from the tree the angle of elevation becomes 30°. The breadth of the river is**- 40 m
- 20 m
- 30 m
- 60 m

Answer: Option B.

Let the breadth of the river be x, Using tangent rule we get,

So x= 20