# Sample Aptitude Questions of Schneider

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1. Shiva gives 20% of her monthly salary to his mother, 50% of the remaining salary he invests in an insurance scheme and PPF in the respective ratio of 5 : 3 and the remaining he keeps in his bank account. If the sum of the amount he gives to his mother and that he invests in PPF is Rs. 12,600, how much is Shiva’s monthly salary?
1. Rs. 36,000
2. . Rs. 64,000
3. Rs. 42,000
4. Rs. 40,000
5. None of these
36000
Let the total amount be x.
0.2x = given to mother.
0.25x= invested in insurance
0.15x= invested in ppf
0.4x= Bank account
Given, 0.2x+0.15x = 0.35x = 12600; x=36000.
2.  The respective ratio of radii of two right circular cylinders (A & B) is 4 : 7. The respective ratio of the heights of cylinders A and B is 2 : 1. What is the respective ratio of volumes of cylinders A and B?
1. 25 :42
2. 23 : 42
3. 32 : 49
4. 30 : 49
5. 36 : 49
32:49
VA:VB = πrA2hA : πrB2hB
= 42x2 : 72x1 = 32:49per formula, ( a + b - c )2 = a2 + b2 + c2 + 2ab – 2bc – 2ac
Therefore, ( 12 + 16 - 22 )2 = 36
1. At present, Aanshi is five years younger to Binny. Binny’s age twenty- years hence will be equal to twice of Aanshi’s age five years ago. What will be Binny’s age eight year hence?
1. 42 years
2. 35 years
3. 30 years
4. 48 years
5. None of these
Let age of Aanshi be A, Bunny be B.
According to equation, A= B-5
Also, B+20 = 2(B-10)
Solving these we get, B= 40. So 8 years hence his age will be 48 years.
2. A number is such that when it is multiplied by 6, it gives another number which is s more than 168 as the original number itself is less than 168. What is 15% of the original number?
1. 8.4
2. 7.8
3. 6.6
4. 8.8
5. 7.2
Let the no. be x.
Now as given, 6x - 168= 168 – x
7x = 336; x= 48
=> 0.15x = 7.2
3. Dharma invested Rs. P for 3 years in scheme A which offered 12% p.a. simple interest. She also invested Rs. P + 400 in scheme B which offered 10% compound interest (compounded annually), for 2 years. If the amount received from scheme A was less than that received from scheme B, by Rs. 304, what is the value of P?
1. Rs. 1400
2. Rs. 1000
3. Rs. 1500
4. Rs. 900
5. Rs. 1200
As given, P + 3*12*P/100 + 304 = (P+400)(1+11/100)2
P(0.15)= 180;
P= 1200
4. Percent profit earned when an article is sold for Rs. 558/- is double the percent profit earned when the same article is sold for Rs. 504/-. If the marked price of the article is 30% above the cost price, what is the marked price of the article?
1. Rs. 585/-
2. Rs. 595/-
3. Rs. 624/-
4. Rs. 590/-
5. Rs. 546/-
Let Percent profit be P
558 = (1+ 2P/100)CP
504 = (1+P/100)CP
Solving these equations we get, CP=Rs.450, p=12%
Now, MP=1.3*450 = Rs.585/-.
5.  Dhruva gave 35% of her monthly salary to her mother. From the remaining salary, she paid 18% towards rent and 42% she kept aside for her monthly expenses. The remaining amount she kept in bank account. The sum of the amount she kept in bank and that she gave to her mother was Rs. 43,920. What was her monthly salary?
1. Rs. 80,000
2. Rs. 75,000
3. Rs. 64,000
4. Rs. 76,000
5. Rs. 72,000
Answer: Option ELet ‘x’ be the monthly salary, then
(65/100 × 40/100)x + 35/100x = 43920
Solving, X= 72000
6. 18 litres of pure water was added to a vessel containing 80 litres of pure milk. 49 litres of the resultant mixture was then sold and some more quantity of pure milk and pure water was added to the vessel in the respective ratio of 2 : 1. If the resultant respective ratio of milk and water in the vessel was 4 : 1, what was the quantity of pure milk added in the vessel? (in litres)
1. 4
2. 8
3. 10
4. 12
5. 2
80(M) + 18(W) = 98
49 liters sold => 49 is left
40(M) + 9(W)
Let x be the quantity of pure milk added
Given, (40 + 2x)/(9 + x) = 4/1
Solving, x = 2
7. There are two motor cycles (A & B) of equal cost price. Motorcycle A was sold at a profit of 14% and motorcycle B was sold for Rs. 4,290/- more than its cost price. The net profit earned after selling both the motor cycles (A & B) is 20%. What is the cost price of each motorcycle?
1. Rs. 16,500/-
2. Rs. 16,000/-
3. Rs. 15,500/-
4. Rs. 71,500/-
5. Rs. 17,000/-