**A dishonest dealer professes to sell his goods at the cost price but uses a weight of 800gm instead of 1kg. Find his real gain percent.**- 25%
- 20%
- 30%
- None of these

Answer: Option A.

200/800 ×100 = 25%**A sum of money lent out at simple interest amounts to Rs. 720 after 2 years and to Rs. 1,020 after a further period of 5 years. The sum and the rate % are**- Rs. 500, 5%
- Rs. 400, 15%
- Rs. 600, 10%
- Rs. 700, 20%

Answer: Option C.

Amount after 2 years = Rs 720

Amount after 7 years = Rs 1020

Therefore, Interest for 5 years = Rs 300

Interest for 1 year = Rs 60

And Interest for 2 years = Rs 120

SO Principal = 720-120 = Rs 600

Also, 120 = (600*R*2)/100 = R = 10%

Amount after 2 years = Rs 720

Amount after 7 years = Rs 1020

Therefore, Interest for 5 years = Rs 300

Interest for 1 year = Rs 60

And Interest for 2 years = Rs 120

SO Principal = 720-120 = Rs 600

Also, 120 = (600*R*2)/100 = R = 10%**A train with 90 km/h crosses a bridge in 36 seconds. Another train 100 metres shorter crosses the same bridge at 45 km/h. What is the time taken by the second train to cross the bridge ?**- 61 seconds
- 63 seconds
- 62 seconds
- 64 seconds

Answer: Option D.

Train A, Speed = 90kmph

=90*(5/18)m/s = 25m/s = 25m/s, t=36s

Let length, L = x+y = time*speed = 25*36 = 900m

=800m, Speed= 45*(5/18) = (25/2) m/s

t= (Distance/Speed) = (800/(25/2)) = (1600/25) = 64 seconds

**Ramesh travels 760 km to his home, partly by train and partly by car He takes 8 hours, if he travels 160 km by train and the rest by car. He takes 12 minutes more, if he travels 240 km by train and the rest by car. What are the speeds of the train and of the car?**- Speed of car = 90 km/h, speed of train = 60 km/h
- Speed of car = 100 km/h, speed of train = 80 km/h
- Speed of car = 80 km/h, speed of train = 70 km/h
- Speed of car = 100 km/h, speed of train = 90 km/h

Answer: Option B.

Let speeds be x and y for train and car respectively.

Then 8 = (160/8) + (600/y) .....(1)

And 8(1/5) = (240/x) + ((760-240)/y) .....(2)

Solving for x and y, we get 100 and 80 km/hr.

You can also use the option straightway for such Qs.**Some students planned a picnic. The budget for food was Rs. 500. But, 5 of them failed to go and thus the cost of food for each member increased by Rs. 5. How many students attended the picnic?**- 15
- 25
- 20
- 30

Answer: Option C.

By direction options,500/25=20 ,500/20=25

By mathematical method, the main steps are: xy = 500 …(1) and (x−5) (y+5) = 500 …(2),

From eqn. 2, x−y = 5 or y = x−5 Put in eqn 1, x(x−5) = 500 or x^{2}-5x-500=0 ,

i.e. x = 25 and attended ones = x − 5 = 20Infosys Preparation Links- Sample Aptitude Questions of Infosys
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**After being set up, a company manufactured 6000 scooters in the third year and 7000 scooters in the seventh year. Assuming that the production increases uniformly by a fixed number every year, what is the production in the tenth year?**- 7850
- 7650
- 7750
- 7950

Answer: Option C.

You can use A.P.,T_{n}=a+(n-1)d ,6000=a+2d.....(1) and 7000 = a + 6d .....(2)

Eqn (2) – Eqn (1) ⇒ 1000=4d,

i.e. d = 250 and a = 6000 − 500 = 5500

T_{10}=5500 + 9 × 250 =7750**The average score of boys in an examination in a school is 71 and that of the girls is 73. The average score of the school is 71.8. The ratio of the number of boys to that of the girls that appeared in the examination is**- 1 : 2
- 3 : 2
- 2 : 2
- 4 : 2

Answer: Option D.

71.8 = (71x+73y)/(x+y)

71.8 (x+ y) = 71x + 73y

0.8x = 1.2y

x:y = 12:8 which is equals to 3:2**The mean monthly salary paid to 75 workers in a factory is Rs. 5,680. The mean salary of 25 of them is Rs. 5,400 and that of 30 others is Rs. 5,700. The mean salary of the remaining workers is**- Rs. 5,000
- Rs. 7,000
- Rs. 6,000
- Rs. 8,000

Answer: Option C

5680*75 = (5400*25+5700*30+x(75-25-30))/75

4,26,00 = 1,35,000 +1, 71,000 + 20x

X = 1,20,000/20, = 6,000**A sum of Rs. 25 was paid for a work which A can do in 32 days, B in 20 days, B and C in 12 days and D in 24 days. How much did C receive if all the four work together?**- Rs. 14/3
- Rs. 16/3
- Rs. 15/3
- Rs. 17/3

Answer: Option B.

B+ C's 1 day's work = ½ and B's 1 day's work = 1/20

Therefore, C's 1 day's work = (1/12) – (1/20) = 4/120 = 1/30

Monet will be distributed according to the ratio of work done i.e A: B: C: D

= 1/32 : 1/20 : 1/30 : 1/24 = 15 :24:16:20

Therefore, C's Share = 16/(15+24+16+20) = Rs 16/3**A man sold two steel chairs for Rs. 500 each. On one, he gains 20% and on other, he loses 12%. How much does he gain or lose in the whole transaction?**- 1.5% gain
- 2% gain
- 1.5% loss
- 2% loss

Answer: Option A.

CP/SP = 100/(100±x) , i.e. Total CP = 417 (500*100/200) + 568(500*100/88)≅ 985

Since CP<SP .Therefore, Profit = 100-985 = 15

P% ≅ 15/985 X 100 ≅ 1.5 %