In a race of 600 metres, A can beat B by 60 metres and in a race of 500 metres, B can beat C by 50 metres. By how many metres will A beat C in a race of 400 metres?
1. 76 metres
2. 80 metres
3. 70 metres
4. 84 metres
Answer: Option A
A runs B runs C runs
600 metres race 600m 540 m
500 metres race 500 m 450m
Combing ratio A runs B runs C runs
300metres - 2700meters - 2430metres
Unitary A runs B runs C runs
Method 400mtres - 360 metres - 324 metres
∴ A beats C by 400-324 = 76 metres.

26 km
32 km
30 km
28 km

Answer: Option B
Total Time = 7hrs
Let the distance travelled by foot @ 8kmph be x kms
∴ distance travlled by bicycle @ 16kmph be (80-x)kms
ATQ. 7hr = x/8 + (80-x)/16
∴ 7 = (2x + 80 - x)/16
∴ x = 32kms

If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 25 men in 3 days?

65mtr.
52mtr.
70mtr.
78mtr.

Answer: Option C
20 men is 6 days can build 112 metres
25 men in 3 days can build = 112*(25/20)x(3/6)
= 70 meters

If the compound interest on a certain sum of money for 3 years at 10% per annum be Rs. 993, what would be the simple interest?
1. Rs. 880
2. Rs. 890
3. Rs. 895
4. Rs. 900
Answer: Option D
Let P = Principal
A - Amount
We have a = P(1 + R/100)³ and CI = A - P
ATQ 993 = P(1 + R/100)³ - P
∴ P = Rs 3000/-
Now SI @ 10% on Rs 3000/- for 3 yrs = (3000 x 10 x 3)/100
= Rs 900/-
What annual installment will discharge a debt of Rs. 4600 due in 4 years at 10% simple interest?
1. 1000
2. 1030
3. 1100
4. None of these
Answer: Option A
Let the annual instalment be Rs. 100. The first instalment will be paid one year from now i.e. 3 years before it is actually due. The second instalment will be paid two years from now i.e. 2 years before it is actually due.
The third instalment will be paid 1 year before it is actually due.
The fourth instalment will be paid on the day the amount is actually due.
On the first instalment the interest will be paid for 3 years, on the second for 2 years, on the third for 1 year, on the fourth for 0 year. In total an interest for 6 years will be paid (3 + 2 + 1 + 0) on Rs. 100 @ 10%. Interest = (100 × 6 × 10)/100 = Rs. 60 and the principal is Rs 100 × 4 = Rs 400. The total loan that can be discharged is Rs. 400 + 60 = Rs. 460. Here the technique of Chain Rule will be applied. I.e. for Rs. 460 the instalment required is Rs. 100, for Rs. 4600 the instalment required is 4600 × 100/460 = Rs. 1000.
A number whose fifth part increased by 5 is equal to its fourth part diminished by 5, is
1. 160
2. 180
3. 200
4. 220
Answer: Option C
x/5 + 5 = x/4 - 5
⇒ x/5 - x/4 = 10
x/20 = 10
⇒ x = 200

IBM Preparation Links

Sample Aptitude Questions of IBM
Careers in IBM
All About IBM
Free Mock IBM Placement Paper
Join free prep course for IBM
Test Pattern & Selection Procedure of IBM

Two numbers are such that the ratio between them is 3 : 5, but if each is increased by 10, the ratio between them becomes 5:7. The numbers are
1. 3, 5
2. 7, 9
3. 13, 22
4. 15, 25
Answer: Option D
No's are in the ratio 3:5
Le the No's be 3x and 5x
ATQ. (3x+10) : (5x+10) = 5:7
∴ x = 5
No's are (15,25)
A man rows downstream 30 km and upstream 18 km, taking 5 hours each time. What is the velocity of the stream (current)?
1. 1.2 km/hr
2. 1.5 km/hr
3. 2.5 km/hr
4. 1.8 km/hr
Answer: Option A
LET X =SPEED OF BOAT AND Y = SPEED OF CURRENT.
⇒ 30/(X+Y)=18/(X-Y)=5 BY SOLVING Y = 1.2
A train 125 metre long is running at 50 km/hr. In what time will it pass a man running at 5 km/hr in the same direction in which the train is going?
1. 25 sec
2. 10 sec
3. 20 sec
4. 15 sec
Answer: Option B
Distance = 125 metres Speed = 50-5 = 45kmph => 45 * (5/18) = 12.5 m/s
Time = 125 / 12.5 = 10 sec.
A is twice as fast as B and B is thrice as fast as C is. The journey covered by C in 42 minutes, will be covered by A in
1. 11 min
2. 14 min
3. 7 min
4. 17 min
Answer: Option C
B is thrice as fast as C
C covers in 42min
∴ B covers in 42/3 = 14 min
A is twice as fast as B
∴ A covers in 14 * (1/2) = 7 min