Sample Aptitude Questions of IBM

  1. In a race of 600 metres, A can beat B by 60 metres and in a race of 500 metres, B can beat C by 50 metres. By how many metres will A beat C in a race of 400 metres?
    1. 76 metres
    2. 80 metres
    3. 70 metres
    4. 84 metres
    Answer: Option A
    A runs B runs C runs
    600 metres race 600m 540 m
    500 metres race 500 m 450m
    Combing ratio A runs B runs C runs
    300metres - 2700meters - 2430metres
    Unitary A runs B runs C runs
    Method 400mtres - 360 metres - 324 metres
    ∴ A beats C by 400-324 = 76 metres.
  2. A man travelled a distance of 80 km in 7 hours partly on foot at the rate of 8 km per hour and partly on bicycle at 16 km per hour. Find the distance travelled on foot.
    1. 26 km
    2. 32 km
    3. 30 km
    4. 28 km
    Answer: Option B
    Total Time = 7hrs
    Let the distance travelled by foot @ 8kmph be x kms
    ∴ distance travlled by bicycle @ 16kmph be (80-x)kms
    ATQ. 7hr = x/8 + (80-x)/16
    ∴ 7 = (2x + 80 - x)/16
    ∴ x = 32kms
  3. If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 25 men in 3 days?
    1. 65mtr.
    2. 52mtr.
    3. 70mtr.
    4. 78mtr.
    Answer: Option C
    20 men is 6 days can build 112 metres
    25 men in 3 days can build = 112*(25/20)x(3/6)
    = 70 meters
  1. If the compound interest on a certain sum of money for 3 years at 10% per annum be Rs. 993, what would be the simple interest?
    1. Rs. 880
    2. Rs. 890
    3. Rs. 895
    4. Rs. 900
    Answer: Option D
    Let P = Principal
    A - Amount
    We have a = P(1 + R/100)3 and CI = A - P
    ATQ 993 = P(1 + R/100)3 - P
    ∴ P = Rs 3000/-
    Now SI @ 10% on Rs 3000/- for 3 yrs = (3000 x 10 x 3)/100
    = Rs 900/-
  2. What annual installment will discharge a debt of Rs. 4600 due in 4 years at 10% simple interest?
    1. 1000
    2. 1030
    3. 1100
    4. None of these
    Answer: Option A
    Let the annual instalment be Rs. 100. The first instalment will be paid one year from now i.e. 3 years before it is actually due. The second instalment will be paid two years from now i.e. 2 years before it is actually due.
    The third instalment will be paid 1 year before it is actually due.
    The fourth instalment will be paid on the day the amount is actually due.
    On the first instalment the interest will be paid for 3 years, on the second for 2 years, on the third for 1 year, on the fourth for 0 year. In total an interest for 6 years will be paid (3 + 2 + 1 + 0) on Rs. 100 @ 10%. Interest = (100 × 6 × 10)/100 = Rs. 60 and the principal is Rs 100 × 4 = Rs 400. The total loan that can be discharged is Rs. 400 + 60 = Rs. 460. Here the technique of Chain Rule will be applied. I.e. for Rs. 460 the instalment required is Rs. 100, for Rs. 4600 the instalment required is 4600 × 100/460 = Rs. 1000.
  3. A number whose fifth part increased by 5 is equal to its fourth part diminished by 5, is
    1. 160
    2. 180
    3. 200
    4. 220
    Answer: Option C
    x/5 + 5 = x/4 - 5
    ⇒ x/5 - x/4 = 10
    x/20 = 10
    ⇒ x = 200
  1. Two numbers are such that the ratio between them is 3 : 5, but if each is increased by 10, the ratio between them becomes 5:7. The numbers are
    1. 3, 5
    2. 7, 9
    3. 13, 22
    4. 15, 25
    Answer: Option D
    No's are in the ratio 3:5
    Le the No's be 3x and 5x
    ATQ. (3x+10) : (5x+10) = 5:7
    ∴ x = 5
    No's are (15,25)
  2. A man rows downstream 30 km and upstream 18 km, taking 5 hours each time. What is the velocity of the stream (current)?
    1. 1.2 km/hr
    2. 1.5 km/hr
    3. 2.5 km/hr
    4. 1.8 km/hr
    Answer: Option A
    LET X =SPEED OF BOAT AND Y = SPEED OF CURRENT.
    ⇒ 30/(X+Y)=18/(X-Y)=5 BY SOLVING Y = 1.2
  3. A train 125 metre long is running at 50 km/hr. In what time will it pass a man running at 5 km/hr in the same direction in which the train is going?
    1. 25 sec
    2. 10 sec
    3. 20 sec
    4. 15 sec
    Answer: Option B
    Distance = 125 metres Speed = 50-5 = 45kmph => 45 * (5/18) = 12.5 m/s
    Time = 125 / 12.5 = 10 sec.
  4. A is twice as fast as B and B is thrice as fast as C is. The journey covered by C in 42 minutes, will be covered by A in
    1. 11 min
    2. 14 min
    3. 7 min
    4. 17 min
    Answer: Option C
    B is thrice as fast as C
    C covers in 42min
    ∴ B covers in 42/3 = 14 min
    A is twice as fast as B
    ∴ A covers in 14 * (1/2) = 7 min
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