Sample Aptitude Questions of IBM

  1. In a race of 600 metres, A can beat B by 60 metres and in a race of 500 metres, B can beat C by 50 metres. By how many metres will A beat C in a race of 400 metres?
    1. 76 metres
    2. 80 metres
    3. 70 metres
    4. 84 metres
    Answer: Option A
    A runs B runs C runs
    600 metres race 600m 540 m
    500 metres race 500 m 450m
    Combing ratio A runs B runs C runs
    300metres - 2700meters - 2430metres
    Unitary A runs B runs C runs
    Method 400mtres - 360 metres - 324 metres
    ∴ A beats C by 400-324 = 76 metres.
  1. 26 km
  2. 32 km
  3. 30 km
  4. 28 km
Answer: Option B
Total Time = 7hrs
Let the distance travelled by foot @ 8kmph be x kms
∴ distance travlled by bicycle @ 16kmph be (80-x)kms
ATQ. 7hr = x/8 + (80-x)/16
∴ 7 = (2x + 80 - x)/16
∴ x = 32kms
  • If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 25 men in 3 days?
    1. 65mtr.
    2. 52mtr.
    3. 70mtr.
    4. 78mtr.
    Answer: Option C
    20 men is 6 days can build 112 metres
    25 men in 3 days can build = 112*(25/20)x(3/6)
    = 70 meters
    1. If the compound interest on a certain sum of money for 3 years at 10% per annum be Rs. 993, what would be the simple interest?
      1. Rs. 880
      2. Rs. 890
      3. Rs. 895
      4. Rs. 900
      Answer: Option D
      Let P = Principal
      A - Amount
      We have a = P(1 + R/100)3 and CI = A - P
      ATQ 993 = P(1 + R/100)3 - P
      ∴ P = Rs 3000/-
      Now SI @ 10% on Rs 3000/- for 3 yrs = (3000 x 10 x 3)/100
      = Rs 900/-
    2. What annual installment will discharge a debt of Rs. 4600 due in 4 years at 10% simple interest?
      1. 1000
      2. 1030
      3. 1100
      4. None of these
      Answer: Option A
      Let the annual instalment be Rs. 100. The first instalment will be paid one year from now i.e. 3 years before it is actually due. The second instalment will be paid two years from now i.e. 2 years before it is actually due.
      The third instalment will be paid 1 year before it is actually due.
      The fourth instalment will be paid on the day the amount is actually due.
      On the first instalment the interest will be paid for 3 years, on the second for 2 years, on the third for 1 year, on the fourth for 0 year. In total an interest for 6 years will be paid (3 + 2 + 1 + 0) on Rs. 100 @ 10%. Interest = (100 × 6 × 10)/100 = Rs. 60 and the principal is Rs 100 × 4 = Rs 400. The total loan that can be discharged is Rs. 400 + 60 = Rs. 460. Here the technique of Chain Rule will be applied. I.e. for Rs. 460 the instalment required is Rs. 100, for Rs. 4600 the instalment required is 4600 × 100/460 = Rs. 1000.
    3. A number whose fifth part increased by 5 is equal to its fourth part diminished by 5, is
      1. 160
      2. 180
      3. 200
      4. 220
      Answer: Option C
      x/5 + 5 = x/4 - 5
      ⇒ x/5 - x/4 = 10
      x/20 = 10
      ⇒ x = 200
    1. Two numbers are such that the ratio between them is 3 : 5, but if each is increased by 10, the ratio between them becomes 5:7. The numbers are
      1. 3, 5
      2. 7, 9
      3. 13, 22
      4. 15, 25
      Answer: Option D
      No's are in the ratio 3:5
      Le the No's be 3x and 5x
      ATQ. (3x+10) : (5x+10) = 5:7
      ∴ x = 5
      No's are (15,25)
    2. A man rows downstream 30 km and upstream 18 km, taking 5 hours each time. What is the velocity of the stream (current)?
      1. 1.2 km/hr
      2. 1.5 km/hr
      3. 2.5 km/hr
      4. 1.8 km/hr
      Answer: Option A
      LET X =SPEED OF BOAT AND Y = SPEED OF CURRENT.
      ⇒ 30/(X+Y)=18/(X-Y)=5 BY SOLVING Y = 1.2
    3. A train 125 metre long is running at 50 km/hr. In what time will it pass a man running at 5 km/hr in the same direction in which the train is going?
      1. 25 sec
      2. 10 sec
      3. 20 sec
      4. 15 sec
      Answer: Option B
      Distance = 125 metres Speed = 50-5 = 45kmph => 45 * (5/18) = 12.5 m/s
      Time = 125 / 12.5 = 10 sec.
    4. A is twice as fast as B and B is thrice as fast as C is. The journey covered by C in 42 minutes, will be covered by A in
      1. 11 min
      2. 14 min
      3. 7 min
      4. 17 min
      Answer: Option C
      B is thrice as fast as C
      C covers in 42min
      ∴ B covers in 42/3 = 14 min
      A is twice as fast as B
      ∴ A covers in 14 * (1/2) = 7 min

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