# Sample Aptitude Questions of SAMSUNG

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1. If G is the centroid of △ABC and △ABC = 48 cm2, then the area of △BGC is
1. 16 cm2
2. 24 cm2
3. 31 cm2
4. 8 cm2

Answer : Option A.

△BGC = 1/3 * △ABC = 1/3 * 48 = 16 sq. cm
2. The diagonals AC and BD of a cyclic quadrilateral ABCD intersect each other at the point P. Then, it is always true that
1. AP x BP = CP x DP
2. AP x CP = AB x CP
3. BP x AB = CD x CP
4. AP x CP = BP x DP

Answer : Option D.

Here, AC and BD are chords of the circle so AP x PC = BP x PD.
1. If tan Θ = 3/4 and Θ is acute, then cosec Θ is
1. 5/4
2. 4/3
3. 4/5
4. 5/3

Answer : Option D.
tan Θ=3/4
cot Θ = 4/3
cosec2Θ - cot2Θ = 1
cosec Θ= √ 1+cot2Θ = √ 1+(4/3)2 = √1+16/9=√25/9=5/3
2. The value of is: 1/(1+tan2)Θ)+1/(1+cot2
1. 2
2. 1/2
3. 1/4
4. 1

Answer : Option D.
Expression
=1/1+tan2Θ+1/1+cot2Θ
1/1+sec2Θ+1/1+cosec2Θ
Cos2Θ+ sin2Θ = 1
3. If O be the circum centre of a triangle PQR and ∠QOR = 110 °, ∠OPR = 25 °, then the measure of ∠PRQ is
1. 55 °
2. 60 °
3. 65 °
4. 50 °

Answer : Option B.

∠QOR = 110 ° ∠OPR = 250 ° ∠QPR = 110 ° / 2 = 55 ° OR = OP ∠OPR = ∠PRO = 25° ∠OQR = ∠ORQ = 70/2 = 35 ° PRQ = 25 ° + 35 ° = 60 °
4. A vertical stick 12 cm long casts a shadow 8 cm long on the ground. At the same time, a tower casts a shadow 40m long on the ground. The height of the tower is
1. 65m
2. 70m
3. 72m
4. 60m

Answer : Option D.
height of Tower/Length Of Stick
=Length of shadow of Tower/Length of shadow of Stick
h/12=40/8
h=40*12/8 = 60 metre
5. A, B, C, D are four points on a circle. AC and BD intersect at a point E such that ∠BEC = 1300 and ∠ECD = 200. ∠BAC is
1. 100 °
2. 110 °
3. 120 °
4. 90 °

Answer : Option B.

∠BEC = 130 °
∠DEC = 180 ° - 130 ° = 50 °
∠EDC = 180 °-50 ° -20 ° = 110 °
∠BAC = ∠EDC = 110 °
(Angle on the same arc)
6. In a triangle, if three altitudes are equal, then the triangle is
1. Right
2. Isosceles
3. Obtuse
4. Equilateral

Answer : Option D.
The only possible case is when the Triangle is equilateral.
7. The tops of two poles of height 24m and 36 m are connected by a wire. If the wire makes an angle of 60 ° with the horizontal, then the length of the wire is
1. 8 m
2. 6 √3 m
3. 6 m
4. 8√3m

Answer : Option D.

DE = 36-24 = 12 metre
From △ADE, Sin 60 ° = DE/AD
√3/2=12/AD
AD = 12 x 2/√3
=8√3 metre
8. The value of 1/cosecΘ-cotΘ-1/sinΘ is
1. Cosec Θ
2. tan Θ
3. 1
4. cot Θ

Answer : Option D.
Expression = 1/cosec Θ - cot Θ - 1/cosec Θ cosec2Θ-cot2Θ/cosecΘ-cotΘ-cosecΘ =cotΘ (cosec2Θ - cot2Θ-1; 1/sinΘ = cosecΘ)
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