**The average score of a cricketer for 13 matches is 42 runs. If his average score for the first 5 matches is 54, then what was his average score (in runs) for last 8 matches?**- 37
- 39
- 34.5
- 33.5

Answer : Option C.

Total Score = Average * Number of matches

Total score of 13 matches = 13 × 42 = 546

Total score of first 5 matches = 5 × 54 = 270

Therefore, total score of last 8 matches = 546 - 270 = 276

Average = 276/8 = 34.5

Hence the answer is option C**If 1/a - 1/b = 1/a-b, then the value of a**^{3}+b^{3}is- 0
- -1
- 1
- 2

Answer : Option A.

**If a**^{2}+b^{2}+c^{2}= ab+bc+ca , then (a+c)/b is equal to- 1
- 2
- 3
- 4

Answer : Option B.

**If the graphs of the equations x + y = 0 and 5y + 7x = 24 intersect at (m, n), then the value of m +n is**- 2
- 1
- 0
- -1

Answer : Option C.

By solving the given two equations, we get the intersection point (12, - 12).

So, m = 12, n = -12

Hence, m + n = 12 – 12 = 0 So, ans. is option C.**A function f(x) is defined as f(x) = f(x – 2) - x(x + 2) for all the integer values of x and f(1) + f(4) = 0. What is the value of f(1) + f(2) + f(3) + f(4) + f(5) + f(6)?**- 0
- 89
- -89
- None of these

Answer : Option C.

Let S = f(1) + f(2) + f(3) + f(4) + f(5) + f(6)

As f(1) + f(4) = 0, therefore S = f(2) + f(3) + f(5) + f(6) ------ (1)

f(2) = f(0) - 8

f(3) = f(1) - 15

f(4) = f(2) - 24 = f(0) - 32

f(5) = f(3) - 35 = f(1) - 50

f(6) = f(4) - 48 = f(0) - 80

Put the above values in equation (1), we get

S = f(0) - 8 + f(1) - 15 + f(1) - 50 + f(0) - 80

S = 2(f(0) + f(1)) - 153 ------ (2)

As we already know f(1) + f(4) = 0 ⇒f(1) + f(0) - 32 = 0 ⇒f(1) + f(0) = 32

Putting this value in equation 2, we get S = 2(32) - 153 = -89

So, Ans is option C.SAP Preparation Links- Sample Aptitude Questions of SAP
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**What annual payment will discharge a debt of Rs. 6,450 due in 4 years at 5% per annum simple interest?**- 1400
- 1500
- 1550
- 1600
- None of these

Answer : Option B.

Let the annual installment be rs. x

therefore (x + x*3*5/100)+(x + x*2*5/100)

+(x + x*1*5/100)+x =6450

=>115x/100+110x/100+105x/100+x=6450

=>115x+110x+105x+100x=6450*100

=>430x=6450*100

x=6450*100/430=rs.1500**The average of the first 100 positive integers is**- 100
- 51
- 50.5
- 49.5
- 49

Answer : Option C.

n(n+1)/2

1+2+3+....+n

therefore average of these numbers=n+1/2

therefore required average

100+1/2=50.5**In a family, the average age of a father and a mother is 35 years. The average age of the father, mother and their only son is 27 years. What is the age of the son?**- 12 years
- 11 years
- 10.5 years
- 10 years
- None of these

Answer : Option B.

Father+Mother=2*35=70 years

Father+Mother+Son=27*3=81 years

therefore Son's age=81-70=11 years**DIRECTIONS for the question 9 and 10 : Solve the following question and mark the most appropriate option****The length and breadth of a rectangle are increased by 20% and 40% respectively. What is the percentage increase in its area?**- 60%
- 68%
- 78%
- Data inadequate

Answer : Option B.

Apply the percentage formula. The percentage increase in the area will be P + Q + PQ / 100. So we get the answer as 20 +

40 + 20 × 40/100 = 68%. i.e. 2nd option.**The diameter of a circle is 21 metres. It will take how many revolutions to cover a distance of 6.6 km?**- 80
- 50
- 200
- 100
^{*}

Answer : Option D.

No. of revolutions = Distance/circumference.

Distance = 6.6 × 1000 = 6600 metres.

Circumference = 2 × 22/7 × 21/2 = 66 metres.

No. of revolutions = 6600/66 = 100 revolutions. i.e. 4thoption