**Type A, 12 kg of rice worth Rs. 40/kg is mixed with Type B, rice worth Rs. 24/kg. What should be the quantity of Type B rice, if the mixture is sold at Rs. 45/kg with 25% profit added in it?**- 18 Kg
- 48 Kg
- 4 Kg
- can't say

Answer : Option C.

C.P. of the mixture = 45/1.25 = Rs. 36/kg.

So, (40-36)/(36-24) = (N)/(12) ⇒ N = 4 Kg**A person spends 1/7th of his salary on travel,1/3rd of the remaining on food, he then spends 1/4th of the remaining on rent. Finally he puts 1/6th of the remaining as a monthly savings, after which he has 25000 left. What is his salary (in Rs.)?**- 70,000
- 14,000
- 84,000
- 26,000

Answer : Option A.

Let M be the total salary

Therefore, as per question, M × (6/7) × (2/3) × (3/4) × (5/6) = Rs 25000

M = Rs 70000

**Point C(x,y) divides the distance AB with point A(8,12) and point B(16, 18) in a ratio of 3:5, with AC being shorter than BC. What are the co-ordinates of C?**- (12,15)
- (14.5, 12.5)
- (14.5, 12.5)
- (11,14.25)

Answer : Option C.

x co-ordinate of C = [(5×8) + (3×16)] / (3+5) = 11

y co-ordinate of C = [(5×12) + (3×18)] / (3+5) = 14.25

Co-ordinates of C is ( 11, 14.25 )**How many terms of the sequence -12, -8, -4,…so on, to make a sum of 120?**- 11
- 12
- 10
- 13

Answer : Option B.

The series is in A.P. where a = -12 and d = 4.

So 120 = (n/2)[2 × (-12) + (n -1) × 4].

On solving this, we get n = 12**The value of a machine depreciates from Rs 32,768 to Rs 21,952 in three years. What is the rate % of depreciation?**- 11%
- 12.25%
- 12.5%
- 33%

Answer : Option C.

Let R be the rate of depriciation, therefore, 21952 = 32768[1-(R/100)]^{3}. On solving this we get R = 12.5%L&T Infotech Preparation Links- Sample Aptitude Questions of L&T Infotech
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**A TV set listed at Rs 3200 is sold to a retailer at a successive discount of 25% and 15%. The retailer desires a profit of 20%, after allowing a discount of 10% to the customer. At what price should he list the TV set (in Rs.)?**- 2720
- 2448
- 2040
- 2133

Answer : Option A.

The retailers C.P. = 3200 × 0.75 × 0.85 = Rs 2040.

His expected S.P. = 2040 × 1.2 = Rs 2448.

But S.P. is 90% of the L.P., as there is a discount of 10%.

So L.P. = 2448/0.9 = Rs 2720**A student is to answer 10 out of 12 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is**- 140
- 280
- 196
- 346

Answer : Option A.

4 questions can be chosen from the first 5 in 5 ways. Remaining 6 questions can be selected from 8 questions in^{8}C_{6 }ways. So required answer is^{8}C_{6 }× 5 = 28 × 5 = 140.**A rectangular playground with the dimension of 50m X 30 m is surrounded by a 5 m wide road all the sides. What is the area of the road?**- 600 sq. m.
- 500 sq. m.
- 450 sq. m.
- 900 sq. m.

Answer : Option D.

AREA OF ROAD= area of bigger rectangle - area of smaller rectangle ⇒(60×40)-(50×30)⇒2400-1500=900.**It takes 5 sec. for a clock to strike at 5’o clock. If the striking intervals are uniform how much time will it take to strike 9’o clock (in sec.)?**- 9
- 10
- 11
- 12

Answer : Option B.

There are 4 intervals in 5 strokes.

Time taken to strike 1 stroke will be 5/4 sec.

At 9, there will be 9 strokes and 8 intervals between two strokes.

Thus time required = 5/4 × 8 = 10 sec**From the top of the Tower which is 240m high, if the angle of depression of a point on the ground is 30°, then the distance of the point from the foot of the Tower is**- 40 √ 3
- 80 √ 3
- 120 √ 3
- 240 √ 3

Answer : Option D.