**The respective ratio of salaries of A and B is 8:7, if the salary of B increases by 20% and the salary of A increases by 21% the new ratio becomes 96 : 77 respectively. What is A's salary?**- Rs. 22,560/-
- Rs. 21,600/-
- Rs. 20,640/-
- Rs. 23.040/-
- Cannot be determined

Answer : Option E.

Only ratio of the salary is given, but salary is not given, so we cannot determined the salary of A . Hence answer is option E.**(1/3)rd the diagonal of a square is 2. What is the measure of the side of the concerned square?**- 12 m
- 9 m
- 18 m
- 6 m
- 7 m

Answer : Option B.

Let a be the side of a square.

Therefore, diagonal (d) = √2a

We are given that

Hence the answer is option B.

**((441)**^{1/2}* 207 * (343)^{1/3})/ ((14)^{2}*(529)^{1/2})=?- 6
^{1}⁄_{2} - 5
^{1}⁄_{2} - 5
^{3}⁄_{4} - 6
^{3}⁄_{4} - 6
^{1}⁄_{4}

Answer : Option D.

((441)^{1/2}* 207 * (343)^{1/3})/ ((14)^{2}*(529)^{1/2})=?

=> 21 * 207 * 7/196*23 = 6^{3/4}

Hence the answer is option D.- 6
**3/8 of {4624 / (564-428)} = ?**- 13
^{1}⁄_{4} - 14
^{1}⁄_{4} - 11
^{5}⁄_{6} - 12
^{3}⁄_{4} - 12
^{1}⁄_{8}

Answer : Option D.

= 3/8 of {4624/ 136}

= 3/8 of 34

Hence the answer is option D.- 13
**3**^{3}⁄_{8}* 6^{5}⁄_{12}- 2^{3}⁄_{16}* 3^{1}⁄_{2}= ?- 21
- 18
- 14
- 15
- 16

Answer : Option C.

? = 3^{3}⁄_{8}* 6^{5}⁄_{12}- 2^{3}⁄_{16}* 3^{1}⁄_{2}

= (27/8) * (77/12) - (35/16) * (7/2)

= (693/32) - (245/32) = 448/32 = 14.

Hence the answer is option C.Hexaware Preparation Links- Sample Aptitude Questions of Hexaware
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**(√4356 * √?) / √6084 = 11**- 144
- 196
- 169
- 81
- 121

Answer : Option C.

Therefore, ? = 13^{2}= 169

Hence answer is option C.**12 years ago the ratio between the ages of A and B was 3 : 4 respectively. The present age of B is 3**^{3}⁄_{4}times of C's present age if C's present age is 16 years, then what is A's present age ? (in years)- 48
- 42
- 60
- 54
- 36

Answer : Option A.

We are given that (A - 12) / (B - 12) = 3/4 ... (1)

and B = 3^{3}⁄_{4}C = (15/4)C ... (2)

Since, C = 16 yrs, put this value in equation (2)

we get B = (15/4) * 16 = 60 years.

Now put this value in equation (1), we get

A - 12 = (3/4) * (60-12) = 36

=> A = 48 yrs.

Hence answer is option A.**M, N, O and P divided Rs. 44,352/- among themselves M took (3/8)th of the money, N took (1/6)th of the remaining amount and the rest was divided among O and P in the ratio of 3:4 respectively. How much did O get as his share?**- Rs. 9,600/-
- Rs. 20,600/-
- Rs. 10,300/-
- Rs. 8,700/-
- Rs. 9,900/-

Answer : Option E.

Share of M = (3/8) * 44352 = 16632/-

Remaining amount = 44352 – 16632 = 27720/-

Share of N = (1/6) * 27720 = 4620/-

Remaining amount = 27720 – 4620 = 23100/-

Share of O = (3/7) * 23100 = 9900/-

Hence answer is option E.**3 ? 14 55 274 1643**- 11
- 5
- 6
- 8
- 7

Answer : Option B.

>Here the given pattern is:

3 ? 14 55 274 1643

The pattern:

3 × 2 – 1 = 5, 5 × 3 – 1 = 14

14 × 4 – 1 = 55, 55 × 5 – 1 = 274

274 × 6 – 1 = 1643, So ? = 5

Hence answer is option B.**The perimeter of a rectangle whose length is 6m more than its breadth is 84m. What would be the area of a triangle whose base is equal to the diagonal of the rectangle and whose height is equal to the length of the rectangle? (in m**^{2})- 324
- 372
- 360
- 364
- 348

Answer : Option C.

Let l, b and d be the length, breadth and diagonal of the rectangle

Therefore, l – b = 6 and 2(l + b) = 84 or l + b = 42

Solving the above equations, we get l = 24m and b = 18m

Therefore, d^{2}= ( l^{2}+ b^{2}) Putting the values, we get

d^{2}= 24^{2}+ 18^{2}= 576 + 324 = 900 => d = 30m

Let b and h be the base and height of the triangle

We are given that b = d = 30m and h = l = 24m

Thus, area of triangle = (1/2)bh = (1/2) * 30 * 24 = 360 m^{2}