**A sum was put at simple interest at a certain rate for 2 years. Had it been put at 3% higher rate, it would have fetched Rs 300 more. The sum is**- 5300
- 5500
- 5000
- None of these

Answer: Option C.

Increase of 3% fetched Rs.300 more.

It is for 2 years.

For 1 year Increase of 3% will fetch Rs.150.

So 1 % will fetch Rs.50

100% = 5000.

- 5:8
- 8:5
- 31:6
- 16:15

Answer: Option D.

Partly division of 1550 is x and x - 1550

5 % of x + 8 % of (1550 – x)

= 0.05x + 0.08(1550 – x)

For 3 years, the total interest is 300.

3[0.05x + 0.08(1550 – x)] = 300

x = 800 and 1550 – x = 750

The ratio of money = 16:15.

Partly division of 1550 is x and x - 1550

5 % of x + 8 % of (1550 – x)

= 0.05x + 0.08(1550 – x)

For 3 years, the total interest is 300.

3[0.05x + 0.08(1550 – x)] = 300

x = 800 and 1550 – x = 750

The ratio of money = 16:15.

- 0.20%
- 0.3%
- 0.25%
- 0.4%

Answer: Option C.

Let x and y be the interest rates.

x% of 3 lakhs – y% of 3 lakhs = 1500

(x– y) % of 3 lakhs = 1500

300000(x – y)/100 = 1500

(x – y) = 0.5% for 2 years For 1 year = 0.25%

Let x and y be the interest rates.

x% of 3 lakhs – y% of 3 lakhs = 1500

(x– y) % of 3 lakhs = 1500

300000(x – y)/100 = 1500

(x – y) = 0.5% for 2 years For 1 year = 0.25%

- 1
- 4
- 3
- 2

Answer: Option D.

Volume of the box = l × b × h = (12 – 2x) (12 – 2x) (x)

Putting x = 1, 2, 3, 4, we get the maximum value of the above equation at

x = 2. So maximum v = 128. i.e. 4th option

Volume of the box = l × b × h = (12 – 2x) (12 – 2x) (x)

Putting x = 1, 2, 3, 4, we get the maximum value of the above equation at

x = 2. So maximum v = 128. i.e. 4th option

- 3 cm
- 2.66 cm
- 2.5 cm
- 5 cm

Answer: Option C.

The sum of the volumes of the new balls will equal the volume of the original ball. So, 1.5^{3 }= 0.75^{3} + 1^{3 }+ r^{3}. Solving this equation gives r = 1.25

So, d = 2.5 cm.

The sum of the volumes of the new balls will equal the volume of the original ball. So, 1.5

So, d = 2.5 cm.

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- 75 cc
- 100 cc
- 96 cc
- Data Insufficient

Answer: Option B.

When tilted, the water level will form the diagonal of the tank and the volume of the water will he half that of the cylinder. Suppose the volume of the cylinder is V. Since 30 ml = 30 cc has spilled out, 4V/5 = 1/2 V + 30.

Solving this equation gives V = 100 cc.

When tilted, the water level will form the diagonal of the tank and the volume of the water will he half that of the cylinder. Suppose the volume of the cylinder is V. Since 30 ml = 30 cc has spilled out, 4V/5 = 1/2 V + 30.

Solving this equation gives V = 100 cc.

- 63,000
- 46,000
- 36,000
- 26,000

Answer: Option C.

A and B invest in the ratio 3 : 4.

A receives 1000 per month so he will get 12000 for a year.

If A receives 39000 in total then 39000 – 12000 = 27000 will be his share.

If 3x = 27000, then 4x = 36000.

A and B invest in the ratio 3 : 4.

A receives 1000 per month so he will get 12000 for a year.

If A receives 39000 in total then 39000 – 12000 = 27000 will be his share.

If 3x = 27000, then 4x = 36000.

- 110
- 10
- 100
- 101

Answer: Option C

Let the total capital is 6 and time is also 6 years.

A invests 1 for 1 year.

B invests 2 for 2 years

Then, C invests 6 – (1 + 2) = 3 for 6 years.

The ratio of investment is A : B : C = 1 : 4 : 18

If total profit is Rs 2300 then A's share

= 1/23 x 2300 = Rs 100

Let the total capital is 6 and time is also 6 years.

A invests 1 for 1 year.

B invests 2 for 2 years

Then, C invests 6 – (1 + 2) = 3 for 6 years.

The ratio of investment is A : B : C = 1 : 4 : 18

If total profit is Rs 2300 then A's share

= 1/23 x 2300 = Rs 100

- Rs 2,70,000; Rs 80,000 and Rs 3,60,000
- Rs 1,70,000; Rs 1,80,000 and Rs 3,60,000
- Rs 2,70,000; Rs 1,80,000 and Rs 3,60,000
- Rs 2,70,000; Rs 1,80,000 and Rs 3,00,000

Answer: Option C.

1st year, A = 3x, B = 2x and C = 4x

2nd year, A = 3x, B = 2x + 270000 and C = 4x

3rd year, A = 3x, B = 2x + 270000 and

C = 4x + 270000

Total investment by A, B and C is

A = 3x + 3x + 3x = 9x

B = 2x + 2x + 2x + 270000 + 270000

= 6x + 540000

C = 4x + 4x + 4x + 270000 = 12x + 270000

After three years the ratio is 3 : 4 : 5

x = 90000.

Thus initial investment

= (3 * 90000): (2 * 90000): (4 * 90000)

` 270000, ` 180000, ` 360000

1st year, A = 3x, B = 2x and C = 4x

2nd year, A = 3x, B = 2x + 270000 and C = 4x

3rd year, A = 3x, B = 2x + 270000 and

C = 4x + 270000

Total investment by A, B and C is

A = 3x + 3x + 3x = 9x

B = 2x + 2x + 2x + 270000 + 270000

= 6x + 540000

C = 4x + 4x + 4x + 270000 = 12x + 270000

After three years the ratio is 3 : 4 : 5

x = 90000.

Thus initial investment

= (3 * 90000): (2 * 90000): (4 * 90000)

` 270000, ` 180000, ` 360000

- 10 gallons
- 12 gallons
- 14 gallons
- 13 gallons

Answer: Option C.

The ratio of milk to total volume of the mixture in the 3 vessels is 8/9, 1/6 and 1/2 respectively. We can consider these values as 16/18, 3/18 and 9/18 respectively. By alligation, we get the ratio in which the two mixtures are mixed as 6:7 respectively. Since the total quantity is 26, the quantity from the 2nd vessel is (7/13) * 26 = 14 gallons.

The ratio of milk to total volume of the mixture in the 3 vessels is 8/9, 1/6 and 1/2 respectively. We can consider these values as 16/18, 3/18 and 9/18 respectively. By alligation, we get the ratio in which the two mixtures are mixed as 6:7 respectively. Since the total quantity is 26, the quantity from the 2nd vessel is (7/13) * 26 = 14 gallons.