The sum of the squares of the digits constituting a two-digit number is 10, and the product of the required number by the number consisting of the same digits written in the reverse order is 403. Find the number.
13
31
41
Both 1 & 2
None of these
Answer : Option D.
1st condition is satisfied by 1st and 2nd options.
2nd condition is also satisfied by both these options because (1)2 + (3)2 = 10 and (3)2 + (1)2 = 10.
Also 31*13 = 403 and 13*31 = 403. So answer is 4th option.
The product of a two-digit number and a number consisting of the same digits written in the reverse order is equal to 2,430. Find the numbers.
45,54
65,56
52,25
35,53
None of these
Answer : Option A.
Try by options. 1st is the correct answer because 45*54 = 2430.
A garrison of 750 men has provisions for 20 weeks. If at the end of 4 weeks, they are re-inforced by 450 men, how long will the provision last?
Rajesh covers a certain distance by bus at 16 km/hr and return back at the starting point on a cycle at 9 km/hr. His average speed for the whole journey is
13.54 km/hr
11 km/hr
15.52 km/hr
11.52 km/hr
None of these
Answer : Option D.
Here, s1 = 16 and s2 = 9.therefore Average speed = = 2*16*9/16*9= 11.52 km/hr.
430% of 25 + 75% of 430 = ?
430
860
516
86
630
Answer : Option A.
430% of 25 + 75% of 430 = x
430/100 ( 25 + 75 ) => x = 430
Approximate value of Square root of 2412 – 1592= ?
320
75
150
180
210
Answer : Option C.
2412 – 1592=(241 – 159)(241 + 159) = 82 × 400 = 32800
Square root of 32800 = 180 approximately
(364 + 514 - ?)/4=200
162
82
78
68
72
Answer : Option C.
(364 + 514 - x)/4 = 200
= 878 – x = 200 × 4 => x = 878 – 800 = 78
The difference between S.I and C.I on certain of money for 3 years at 10% per annum is Rs. 248. Find the sum?
2000
8000
16000
4000
None of these
Answer : Option B.
Let us consider sum of money is Rs. 1000. S.I. =1000*10*3/100= 300 C.I. = 1000(1+10/100)3 – 1000 = 331 Difference between SI and CI = 331 – 300 = 31 Rs. 31 is difference, when sum = Rs. 1000 Rs. 248 is Difference, then sum =1000*248/31= 8000
