**The sum of the squares of the digits constituting a two-digit number is 10, and the product of the required number by the number consisting of the same digits written in the reverse order is 403. Find the number.**- 13
- 31
- 41
- Both 1 & 2
- None of these

Answer : Option D.

1st condition is satisfied by 1st and 2nd options.

2nd condition is also satisfied by both these options because (1)^{2}+ (3)^{2}= 10 and (3)^{2}+ (1)^{2}= 10.

Also 31*13 = 403 and 13*31 = 403. So answer is 4th option.**The product of a two-digit number and a number consisting of the same digits written in the reverse order is equal to 2,430. Find the numbers.**- 45,54
- 65,56
- 52,25
- 35,53
- None of these

Answer : Option A.

Try by options. 1st is the correct answer because 45*54 = 2430.

**A garrison of 750 men has provisions for 20 weeks. If at the end of 4 weeks, they are re-inforced by 450 men, how long will the provision last?**- 8 weeks
- 12 weeks
- 14 weeks
- 15 weeks
- 10 weeks

Answer : Option E.

750*20 = 750*4+1200*W =>W = 10 weeks**If 8 men can reap 80 hectares in 24 days, how many hectares can 36 men reap the same field in 36 days?**- 540 hectares
- 450 hectares
- 420 hectares
- 489 hectares
- None of these

Answer : Option A.

H = 80*36/8*36/24= 540 hectares**A person covers half of his journey at 30 km/hr and the remaining half at 20 km/hr. The average speed for the whole journey is**- 18 km/hr
- 28 km/hr
- 32 km/hr
- 20 km/ hr
- 24 km/hr

Answer : Option E.

Here, s1 = 30 and s2 = 20.therefore Average speed = =2*30*20/30+20 = 24 km/hr.SanDisk Preparation Links- Sample Aptitude Questions of SanDisk
- All About SanDisk
- Free Mock SanDisk Placement Paper
- Join free prep course for SanDisk
- Test Pattern & Selection Procedure of SanDisk

**Rajesh covers a certain distance by bus at 16 km/hr and return back at the starting point on a cycle at 9 km/hr. His average speed for the whole journey is**- 13.54 km/hr
- 11 km/hr
- 15.52 km/hr
- 11.52 km/hr
- None of these

Answer : Option D.

Here, s1 = 16 and s2 = 9.therefore Average speed = = 2*16*9/16*9= 11.52 km/hr.**430% of 25 + 75% of 430 = ?**- 430
- 860
- 516
- 86
- 630

Answer : Option A.

430% of 25 + 75% of 430 = x

430/100 ( 25 + 75 ) => x = 430**Approximate value of Square root of 241**^{2}– 159^{2}= ?- 320
- 75
- 150
- 180
- 210

Answer : Option C.

241^{2}– 159^{2}=(241 – 159)(241 + 159) = 82 × 400 = 32800

Square root of 32800 = 180 approximately**(364 + 514 - ?)/4=200**- 162
- 82
- 78
- 68
- 72

Answer : Option C.

(364 + 514 - x)/4 = 200

= 878 – x = 200 × 4 => x = 878 – 800 = 78**The difference between S.I and C.I on certain of money for 3 years at 10% per annum is Rs. 248. Find the sum?**- 2000
- 8000
- 16000
- 4000
- None of these

Answer : Option B.

Let us consider sum of money is Rs. 1000. S.I. =1000*10*3/100= 300 C.I. = 1000(1+10/100)^{3}– 1000 = 331 Difference between SI and CI = 331 – 300 = 31 Rs. 31 is difference, when sum = Rs. 1000 Rs. 248 is Difference, then sum =1000*248/31= 8000