**Simple interest on Rs. 1200 @ 13 p.c.p.a. for 'X' years is Rs. 624/-. What is the amount on Rs. 'X+1000' at the same rate of interest for 3 years?**- Rs. 1872/-
- Rs. 1384/-
- Rs. 936/-
- Other than those given as options
- Rs. 1404/-

Answer : Option D.624 = (1200×13×x)/100 => x = 4

Now, P = x + 1000 = 4 + 1000 = 1004

I = (1004×13×3)/100 = 392

=> amount = 1004 + 392 = 1396/-**A circle and rectangle have the same perimeter. The sides of the rectangle are 18 cm and 26 cm. What will be the area of the circle? (in cm**^{2})- 88
- 1250
- 154
- 128
- Other than those given as options

Answer : Option E .Perimeter of rectangle = perimeter of circle = 2 (18 + 26) = 88

2Πr = 88 => r = 14cm

Area of circle = 22/7 ×14 × 14 = 616 cm^{2}

**101 + 1001 + 2003 + 30005 + 9056 =?**- 42616
- 42166
- 41266
- 42156
- 42661

Answer : Option B.=>101 + 1001 + 2003 + 30005 + 9056 = 42166.**5/6**^{th}of 348 -1/8^{th}of 232 = ?- 267
- 258
- 257
- 261
- 263

Answer : Option D.=>5/6=> x = 290 – 29 = 261^{th}of 348 -1/8^{th}of 232 = x**3060 -2460 = ? × 30**- 30
- 50
- 20
- 60
- 43

Answer : Option C.=>3060 -2460 = x * 30=> 600 = 30x => x = 20Nokia Preparation Links- Sample Aptitude Questions of Nokia
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**The product of the digits of a two-digit number is twice as large as the sum of its digits. If we subtract 27 from the required number, we get a number consisting of the same digits written in the reverse order. Find the number.**- 36
- 27
- 63
- 46
- None of these

Answer : Option C.Go by options. 3Hence product of digits is twice as the sum of the digits. Also 63 – 27 = 36. So digits are reversed.^{rd}option is the answer because 63 Þ product of digits = 6*3 = 18. Sum of digits = 6 + 3 = 9.**The product of the digits of a two-digit number is one-third of that number. If we add 18 to the required number we get a number consisting of the same digits written in reverse order. Find the number.**- 42
- 24
- 72
- 27
- None of these

Answer : Option B.Go by options 2nd option correct because 24 = 3*2*4 . Number is thrice the product of its digits24+18 = 42. Hense digits are reversed.**Jar A has 60 litres of mixture of milk and water in the respective ratio of 2: 1. Jar B which had 40 litres of mixture of milk and water was emptied into Jar A, as a result in Jar A, the respective ratio of milk and water becomes 13 : 7. What was the quantity of water in Jar B?**- 8 litres
- 15 litres
- 22 litres
- 7 litres
- 1 litres

Answer : Option B.Jar A has 60 Liters.Radio between milk and water 2:1;Quantityof milk in Jar A=2/3*60 = 40;Quantityof waterin Jar A=1/3*60 = 20;40 Liters of Mixture B having Milk and Water is empty;Therefore ,total Mixture = 60 + 40 =100;The respective Ratio of Milk and Water is 13:7;Quantity of Milk in Jar A = 13 /20 *100 = 65;Quantity of Waterin Jar A = 7/20 *100 = 35;Quantity of Waterin Jar B = 35 -20 = 15 liters.**The sum of a series of 5 consecutive odd numbers is 195. The second lowest number of this series is one less than the second highest number of another series of 5 consecutive even numbers. What is 40% of the second lowest number of the series of consecutive even numbers?**- 16.8
- 14.8
- 19.4
- 17.6
- 13.6

Answer : Option E.The sum of the series of 5 Consecutive odd numbers is 195;Let the Series of Consecutive odd numbers is X, X+2, X+4, X+6, X+8 ;X+X+2+X+4+X+6+X+8 = 195 ;5X+20 = 195;X=35.Series of consecutive odd numbers is 35, 37 , 39 , 41 ,43 ;According to the question ,the second lowest number of this series is less than the ;Second highest number of another series of 5 consecutive numbers;Second lowest number is 37;Second highest number of another series of 5 consecutive numbers = 37 +1 = 38 ;Therefore , another series of 5 consecutive no 32 , 34 ,36 ,38 , 40 ;40% of the lowest of the series of consecutive numbers = 34 *40 / 100 = 13.6.**The sum of the dimensions of a room (i.e. length, breadth and height) is 18 metres and its length, breadth and height are in the ratio of 3 : 2 : 1 respectively. If the room is to be painted at the rate of Rs. 15 per m**^{2}, what would be the total cost incurred on painting only the four walls of the room (in Rs.)?- 3250
- 2445
- 1350
- 2210
- 2940

Answer : Option C.

Ratio of length : breadth : height = 3 : 2 : 1

Sum of dimensions of room = 18

Length = 3/6×18 = 9

Breath = 2/6×18 = 6

Height = 1/6×18 = 3

Area of four walls = 2h×(l+b) = 2×3(9+6) = 90

Total cost of painting four walls = 90×15 = 1350