A man can row 13 kmph downstream and 9 kmph upstream. What is the speed of the man in still water? (in kmph)
Answer : Option C. Speed of stream = s Speed of man in still water = b ATQ b + s = 13 b – s = 9 ⇒ b = 11, s = 2 Hence, Option 3.
A is 60% more efficient than B. In how many days will ‘A’ and ‘B’ working together complete a piece of work which ‘A’ alone takes 15 days to finish?
Answer : Option E. As A is 60% more efficient than B ⇒ We can suppose that if B does 5 units/days then A does 8 units/day. Work done by A in 15 days = 120 units. A and B working together do 13 units in a day. ⇒ A and B can do 120 units of work in 120/13 Days. Hence, Option 5.
The sum of the digits of a two-digit number is 12 and when the digits of the two-digit number are interchanged, the new number is 36 more than the original number. What is the original two digit number?
Cannot be determined
Answer : Option C. Let ‘ab’ be the Required Number a+b=12….(i) ATQ ba=ab+36 10b+a=10a+b+36 9(b-a)=36 b-a=4….(ii) From eqn. (i) and (ii) b=8, a=4 ⇒ Required Number = 48, Hence, Option (3).
A car covers the first 39 kms of its Journey in 40 minutes & covers the remaining 25 kms in 35 minutes. What is the average speed of the car?
None of these
Answer : Option E. Average Speed = Total Distance Traveled / Total Time Taken = (64*60)/75 = 51.2 km/hr. Hence,Option 5.
A, B and C entered into a partnership by investing Rs. 64,000/-, Rs. 52,000/- and Rs. 36,000/- respectively. All of them invested for equal period of time. If A got Rs. 35,584/- as his share of annual profit, what amount did C get as his share of annual profit?
Answer : Option E. As time is same therefore
Profit of C= (36000/64000)*35584 =Rs.20,016/-. Hence, Option 5.
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