Aricent Aptitude Questions | Aptitude Test For Aricent

A, B and C started a business by investing Rs. 12,800/-. Rs.16,800/- and Rs. 9,600/- respectively. If after 8 months B received Rs. 13,125/- as his share of profit, what amount did C get as his share of profit?
1. Rs. 7,800/-
2. Rs. 7,150/-
3. Rs. 7,750/-
4. Rs. 8,250/-
5. Rs. 7,500/-
Answer: Option E
Here the profit will be distributed in the ratio of their investments
i.e. 12800:16800:9600 → 16:21:12
Let 'x' be the total profit
we know that profit received by B = 13125/-
Therefore,
21 / (16+21+12) * x = 13125
Share received by C = (12 / 49) * 30625 = 7500/-
Hence, the answer is E.

4¹⁄₂ + (1 ÷ 2⁸⁄₉) - 3¹⁄₁₃ = ?
1. 1⁹⁄₂₆
2. 2⁷⁄₁₃
3. 1¹¹⁄₂₆
4. 2⁴⁄₁₃
5. 1¹⁰⁄₁₃
Answer: Option E
4¹⁄₂ + (1 ÷ 2⁸⁄₉) - 3¹⁄₁₃
=> 9/2 + 9/26 - 40/13
=> 1¹⁰⁄₁₃
{√7744 * 11²} ÷ (2)³ = (?)³
1. 7
2. 9
3. 11
4. 13
5. 17
Answer: Option C
? = [{√7744 * 11²} ÷ (2)³]^¹⁄₃
[(88 * 121) / 8]^¹⁄₃
= (1331)^¹⁄₃ = 11
Hence the answer is option C.
456 ÷ 24 * 38 - 958 + 364 = ?
1. 112
2. 154
3. 128
4. 136
5. 118
Answer: Option C
Applying BODMAS
? = 456 ÷ 24 * 38 - 958 + 364
= 19 * 38 - 958 + 364
= 722 - 958 + 364
= 1086 - 958
= 128
Hence, the answer is option C.
(34.5 × 14 × 42) ÷ 2.8 =?
1. 7150
2. 7365
3. 7245
4. 7575
5. 7335
Answer: Option C
? = (34.5 × 14 × 42) ÷ 2.8
= 20286 / 2.8
= 7245
Hence, the answer is option C.

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(3⁶⁄₁₇ ÷ 2⁷⁄₃₄ - 1⁹⁄₂₅) = (?)²
1. 2/5
2. 1/3
3. 4/5
4. 1/5
5. 3/5
Answer: Option A
(?)² = (3⁶⁄₁₇ ÷ 2⁷⁄₃₄ - 1⁹⁄₂₅)
= [(57/17) / (75/34)] - 34/25
= 4/25
Therefore, ? = 2/5
Hence, answer is option A.
-676.76 + 1237.87 + 897.34 - ? = 1294.25
1. 168.6
2. 164.2
3. 156.4
4. 172.2
5. 158.6
Answer: Option B
Applying BODMAS
? = -676.76 + 1237.87 + 897.34 - 1294.25
= 164.2
Hence, the answer is option B.
Pure milk costs Rs. 16/- per liter. After adding water the milkman sells the mixture @ Rs. 15/- per liter and thereby makes a profit of 25% in what respective ratio does he mix milk with water?
1. 3 : 1
2. 4 : 3
3. 3 : 2
4. 5 : 3
5. 4 : 1
Answer: Option A
If SP of mixture is 15/- per liter and profit is 25%, then
CP of mixture = (100/125) * 15 = 12/- liter
As 16/- is the cost of pure 1000 ml, therefore, for 12/-, the quantity of milk =
(12/16) * 1000 = 750 ml
So for 12/- per liter, the milk is 750 ml, then water will be 250 ml.
Thus, required ratio = 750:250 = 3:1
Hence answer is option A.
What will come in place of question mark (?) in the given question?
36 38.8 42.8 ? 54.4 62
1. 46.2
2. 46.6
3. 48.2
4. 48
5. 49
Answer: Option B
Here the given pattern is as follows:
36      38.8      42.8      ?      54.4      62
+2.8      +4.0      +5.2      +6.4      +7.6
+1.2      +1.2      +1.2      +1.2
So ? = 42.8 + 5.2 = 48
Hence answer is option D.
A merchant bought some goods worth Rs. 6,000/- and sold half of them at 12% profit. At what profit percent should he sell the remaining goods to make an overall profit of 18%?
1. 24%
2. 28%
3. 18%
4. 20%
5. 26%
Answer: Option A
Let CP_T = 6000/-
Therefore, cost of half of goods CP₁= 3000/- and of other half goods = CP₂= 3000/-
So, SP₁=3000 × 1.12 = 3360/- and SP_T= 6000 × 1.18 = 7080/-
Thus, SP₂= 7080 – 3360 = 3720/-
Profit % = [(3720 - 3000) / (3000)] * 100 = 24%
Hence answer is option A