Capgemini Aptitude Questions

Aptitude questions form a part of the game-based section of Capgemini written test. These are based on the basic mathematical and reasoning concepts of puzzles, arithmetic operations, grids, etc. Aptitude section is a mix of moderate and slightly difficult questions. Here, we have given certain questions on fundamental topics, that will help you prepare for Capgemini aptitude test:

A 30% loss on cost price is what percent loss on selling price?
1. 30%
2. 20%
3. 15%
4. None of these
Answer: Option D
Let CP = 100 ; SP=70
Loss= 30/70 × 100 = 42.85%
A, B and C hire a taxi for Rs. 2400 for one day. A, B and C used the car for 6 hours, 8 hours and 10 hours respectively. How much did C pay?
1. Rs. 800
2. Rs. 1000
3. Rs. 600
4. Rs. 1200
Answer: Option B
Let total fair be = 2400 ;
Therefore c share =10/24 × 2400 = 1000

The ratio of investments of A and B is 8 : 7 and the ratio of their yearend profits is 20 : 21. If B invested for 12 months, then find the period of investment of A:
1. 6 months
2. 8 months
3. 10 months
4. 12 months
Answer: Option C
Let A invest for x months ; A = 8x months,
B = 7 × 12 = 84 months
8x/84 = 20/21
⇒ x = 10

What percent is 2 minutes 24 seconds of an hour?
1. 6%
2. 2%
3. 4%
4. 8%
Answer: Option C
%=144/60×60 = 4%
Evaluate: 3 cos 80° cosec 10° + 2 cos 59° cosec 31°
1. 1
2. 3
3. 2
4. 5
Answer: Option D
3 cos 80°. Cosec 10° + 2 cos 59° . cosec 31°
= 3 cos (90° - 10°). Cosec 10° + 2 cos (90° - 31°).Cosec 31°
=3sin10°.Cosec10° +2sin31°.cosec31°
=3+2=5

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The total cost of 8 buckets and 5 mugs is Rs. 92 and the total cost of 5 buckets and 8 mugs is Rs. 77. Find the cost of 2 mugs and 3 buckets.
1. Rs. 35
2. Rs. 70
3. Rs. 30
4. Rs. 38
Answer: Option A
CP of 1 bucket = Rs. X
CP of 1 mug = Rs. Y
∴ 8x + 5y = 92....... (i)
5x + 8y = 77........(ii)
By equation (i) × 5 – equation (ii) × 8.
40x + 25y – 40x – 64y
= 460 – 616 ⇒ − 39y = - 156⇒ y = 4
From equation (i),
8x + 20 = 92 ⇒8x = 92 – 20 = 72 ⇒ x = 9
∴ CP of 2 mugs and 3 buckets
= 2 × 4 + 3 × 9 = 8 + 27 = Rs. 35
If 4x/3 + 2P = 12 for what value of P, x = 6?
1. 6
2. 4
3. 2
4. 1
Answer: Option C
When x = 6, (4 * 6)/3 + 2P = 12
⇒ 8 + 2P = 12
⇒ 2P = 12 – 8 = 4
⇒ P = 2
What number must be added to the expression 16a² – 12a to make it a perfect square?
1. 9/4
2. 11/2
3. 13/2
4. 16
Answer: Option A
a² - 2ab + b² = (a-b)²
∴ 16a² – 12a = (4a)² - 2*4a*3/2
Hence, on adding (3/2)² = 9/4, expression will be a perfect square.
The straight line 2x + 3y = 12 passes through:
1. 1st, 2nd and 3rd quadrant
2. 1st, 2nd and 4th quadrant
3. 2nd, 3rd and 4th quadrant
4. 1st, 3rd and 4th quadrant
Answer: Option B
The usual way to solve these type of questions is to put x = 0 once and find y coordinate. This would represent the point where the line cuts the Y axis.
Similarly put y = 0 once and find x coordinate. This would represent the point where the line cuts the X axis. Then join these points and you will get the graph of the line.
So when we put x = 0 we get y = 4.
When we put y = 0 we get x = 6.
So when we join these points we see that we get a line in 1st quadrant, which when extended both sides would go to 4th and 2nd quadrants. So option B.
In ΔABC, ∠A + ∠B = 65°, ∠B + ∠C = 140°, then find ∠B.
1. 40°
2. 25°
3. 35°
4. 20°
Answer: Option B
∠A + ∠B = 65°
∴ ∠C = 180° - 65° = 115°
∠B + ∠C = 140°
∴ ∠B = 140° - 115° = 25°