# Sample Aptitude Questions of Reliance Industries

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1. Product of two co-prime numbers is 117. Then their L.C.M. is
1. Rs 3
2. Rs 39
3. Rs 117
4. Rs 9

HCF of two prime numbers =1
∴ Product of numbers = HCF * LCM
LCM = 117
2. The diameters of two circles are the side of a square and the diagonal of the square respectively. The ratio of the areas of the smaller circle and the larger circle is
1. √2 : √3
2. 1 : √3
3. 1 : 2
4. 1 : 4

Side of square = x units
Diagonal of square =√2x units
Radius of smaller circle =x/2 units
Radius of larger circle =√2x/2=x/√2 units
⇒ Required ratio of areas = π(x2/4).π(x2/2)
= 2 : 4 = 1 : 2
1. The total surface area of a sphere is 8π square unit. The volume of the sphere is
1. (8√3)π cubic unit
2. (8√3/5)π cubic unit
3. (8√2/3)π cubic unit
4. (8/3) π cubic unit

Surface area of sphere = 4πr2 ⇒ r2 = 2 ⇒ r ⇒√2 units
⇒ Volume of sphere
=(4/3)πr3=(4/3)π * (√2)3=(8√2/3)πcubic units
2. A conical flask is full of water.The flask has base radius r and height h. This water is poured into a cylindrical flask of base radius mr. The height of water in the cylindrical flask is
1. (2h)/m
2. h/(3m2)
3. m/(2h)
4. (h/2).m2

Volume of water in conical flask =(1/3)πr2h
If the height of water level in cylindrical flask be H units, then πm2r2H =(1/3)πr2h
⇒H=(1/3).((πr2h)/(πm2r2))= h/(3m2)
3. A and B together can complete; a piece of work in 12 days, B and C can do it in 20 days and C and A can do it in 15 days. A, B and C together can complete it in
1. 8 days
2. 10 days
3. 12 days
4. 6 days

(A+B)’s 1 day’s work = 1/12
(B+C)’s 1 day’s work = 1/20
(C+A)’s 1 day’s work = 1/15
On adding all there, 2(A+B+C)’s day’s work = (1/12)+(1/20)+(1/15)=1/5
⇒(A+B+C)’s 1 day’s work = 1/10
Hence, the work will be finished in 10 days.
4. A and B together can complete a work in 3 days. They start together. But, after 2 days, B left the work. If the work is completed after 2 more days. B alone could do the work in
1. 6 days
2. 8 days
3. 10 days
4. 4 days

(A+B)’s 2 day’s work = 2/3
Remaining work = 1- (2/3)= 1/3
Time taken by A in 1/3 doing work = 2 days
Time taken by A in completing the work = 6 days
B’s 1 day’s work = (1/3)-(1/6)= 1/6
B alone will complete the work in 6 days
5. A does 20% less work than B. If A can complete a piece of work in 15/2 hours, then B can do it in
1. 6 hours
2. 8 hours
3. 10 hours
4. 4 hours

Efficiency of A and B = 4 : 5
Ratio of respective time = 5 : 4
⇒Time taken by B = (4/5)*(15/2)= 6 hours
6. A rational number between 3/4 and 3/8 is
1. 16/9
2. 9/16
3. 12/7
4. 7/3

3/4 = (3 * 4)/(4 * 4) = 12/16  3/8 = 6/16 ⇒ 6/16,7/16,8/16,9/16,10/16,11/16,12/16 ⇒ Required rational number = 9/16.
7. The number of ways in which letters of the word PRAISE be arranged
1. 500
2. 1200
3. 200
4. 700

Let the prices of school bag and shoes is 7x and 5x.
Given that 7x - 5x = 200 ⇒ 2x = 200 ⇒ x = 100.
So the price of a pair of shoes = 5x = 5 * 100 = 500
8. A sum of Rs. 300 is divided among P, Q and R in such a way that Q gets Rs. 30 more than P and R gets Rs. 60 more than Q. The ratio of their share is
1. 3 : 2 : 5
2. 2 : 5 : 3
3. 5 : 3 : 2
4. 2 : 3 : 5