# Sample Aptitude Questions of Reliance Industries

1. Product of two co-prime numbers is 117. Then their L.C.M. is
1. Rs 3
2. Rs 39
3. Rs 117
4. Rs 9

HCF of two prime numbers =1
∴ Product of numbers = HCF * LCM
LCM = 117
2. The diameters of two circles are the side of a square and the diagonal of the square respectively. The ratio of the areas of the smaller circle and the larger circle is
1. √2 : √3
2. 1 : √3
3. 1 : 2
4. 1 : 4

Side of square = x units
Diagonal of square =√2x units
Radius of smaller circle =x/2 units
Radius of larger circle =√2x/2=x/√2 units
⇒ Required ratio of areas = π(x2/4).π(x2/2)
= 2 : 4 = 1 : 2
1. The total surface area of a sphere is 8π square unit. The volume of the sphere is
1. (8√3)π cubic unit
2. (8√3/5)π cubic unit
3. (8√2/3)π cubic unit
4. (8/3) π cubic unit

Surface area of sphere = 4πr2 ⇒ r2 = 2 ⇒ r ⇒√2 units
⇒ Volume of sphere
=(4/3)πr3=(4/3)π * (√2)3=(8√2/3)πcubic units
2. A conical flask is full of water.The flask has base radius r and height h. This water is poured into a cylindrical flask of base radius mr. The height of water in the cylindrical flask is
1. (2h)/m
2. h/(3m2)
3. m/(2h)
4. (h/2).m2

Volume of water in conical flask =(1/3)πr2h
If the height of water level in cylindrical flask be H units, then πm2r2H =(1/3)πr2h
⇒H=(1/3).((πr2h)/(πm2r2))= h/(3m2)
3. A and B together can complete; a piece of work in 12 days, B and C can do it in 20 days and C and A can do it in 15 days. A, B and C together can complete it in
1. 8 days
2. 10 days
3. 12 days
4. 6 days

(A+B)’s 1 day’s work = 1/12
(B+C)’s 1 day’s work = 1/20
(C+A)’s 1 day’s work = 1/15
On adding all there, 2(A+B+C)’s day’s work = (1/12)+(1/20)+(1/15)=1/5
⇒(A+B+C)’s 1 day’s work = 1/10
Hence, the work will be finished in 10 days.
4. A and B together can complete a work in 3 days. They start together. But, after 2 days, B left the work. If the work is completed after 2 more days. B alone could do the work in
1. 6 days
2. 8 days
3. 10 days
4. 4 days

(A+B)’s 2 day’s work = 2/3
Remaining work = 1- (2/3)= 1/3
Time taken by A in 1/3 doing work = 2 days
Time taken by A in completing the work = 6 days
B’s 1 day’s work = (1/3)-(1/6)= 1/6
B alone will complete the work in 6 days
5. A does 20% less work than B. If A can complete a piece of work in 15/2 hours, then B can do it in
1. 6 hours
2. 8 hours
3. 10 hours
4. 4 hours

Efficiency of A and B = 4 : 5
Ratio of respective time = 5 : 4
⇒Time taken by B = (4/5)*(15/2)= 6 hours
6. A rational number between 3/4 and 3/8 is
1. 16/9
2. 9/16
3. 12/7
4. 7/3

3/4 = (3 * 4)/(4 * 4) = 12/16  3/8 = 6/16 ⇒ 6/16,7/16,8/16,9/16,10/16,11/16,12/16 ⇒ Required rational number = 9/16.
7. The number of ways in which letters of the word PRAISE be arranged
1. 500
2. 1200
3. 200
4. 700