**Product of two co-prime numbers is 117. Then their L.C.M. is**- Rs 3
- Rs 39
- Rs 117
- Rs 9

Answer : Option C.

HCF of two prime numbers =1

∴ Product of numbers = HCF * LCM

LCM = 117**The diameters of two circles are the side of a square and the diagonal of the square respectively. The ratio of the areas of the smaller circle and the larger circle is**- √2 : √3
- 1 : √3
- 1 : 2
- 1 : 4

Answer : Option C.

Side of square = x units

Diagonal of square =√2x units

Radius of smaller circle =x/2 units

Radius of larger circle =√2x/2=x/√2 units

⇒ Required ratio of areas = π(x^{2}/4).π(x^{2}/2)

= 2 : 4 = 1 : 2

**The total surface area of a sphere is 8π square unit. The volume of the sphere is**- (8√3)π cubic unit
- (8√3/5)π cubic unit
- (8√2/3)π cubic unit
- (8/3) π cubic unit

Answer : Option C.

Surface area of sphere = 4πr^{2}⇒ r^{2}= 2 ⇒ r ⇒√2 units

⇒ Volume of sphere

=(4/3)πr^{3}=(4/3)π * (√2)^{3}=(8√2/3)πcubic units**A conical flask is full of water.The flask has base radius r and height h. This water is poured into a cylindrical flask of base radius mr. The height of water in the cylindrical flask is**- (2h)/m
- h/(3m
^{2}) - m/(2h)
- (h/2).m
^{2}

Answer : Option B.

Volume of water in conical flask =(1/3)πr^{2}h

If the height of water level in cylindrical flask be H units, then πm^{2}r^{2}H =(1/3)πr^{2}h

⇒H=(1/3).((πr^{2}h)/(πm^{2}r^{2}))= h/(3m^{2})**A and B together can complete; a piece of work in 12 days, B and C can do it in 20 days and C and A can do it in 15 days. A, B and C together can complete it in**- 8 days
- 10 days
- 12 days
- 6 days

Answer : Option B.

(A+B)’s 1 day’s work = 1/12

(B+C)’s 1 day’s work = 1/20

(C+A)’s 1 day’s work = 1/15

On adding all there, 2(A+B+C)’s day’s work = (1/12)+(1/20)+(1/15)=1/5

⇒(A+B+C)’s 1 day’s work = 1/10

Hence, the work will be finished in 10 days.Reliance Industries Preparation Links- Sample Aptitude Questions of Reliance Industries
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**A and B together can complete a work in 3 days. They start together. But, after 2 days, B left the work. If the work is completed after 2 more days. B alone could do the work in**- 6 days
- 8 days
- 10 days
- 4 days

Answer : Option A.

(A+B)’s 2 day’s work = 2/3

Remaining work = 1- (2/3)= 1/3

Time taken by A in 1/3 doing work = 2 days

Time taken by A in completing the work = 6 days

B’s 1 day’s work = (1/3)-(1/6)= 1/6

B alone will complete the work in 6 days**A does 20% less work than B. If A can complete a piece of work in 15/2 hours, then B can do it in**- 6 hours
- 8 hours
- 10 hours
- 4 hours

Answer : Option A.

Efficiency of A and B = 4 : 5

Ratio of respective time = 5 : 4

⇒Time taken by B = (4/5)*(15/2)= 6 hours**A rational number between 3/4 and 3/8 is**- 16/9
- 9/16
- 12/7
- 7/3

Answer : Option B.

3/4 = (3 * 4)/(4 * 4) = 12/16 3/8 = 6/16 ⇒ 6/16,7/16,8/16,9/16,10/16,11/16,12/16 ⇒ Required rational number = 9/16.**The number of ways in which letters of the word PRAISE be arranged**- 500
- 1200
- 200
- 700

Answer : Option A.

Let the prices of school bag and shoes is 7x and 5x.

Given that 7x - 5x = 200 ⇒ 2x = 200 ⇒ x = 100.

So the price of a pair of shoes = 5x = 5 * 100 = 500**A sum of Rs. 300 is divided among P, Q and R in such a way that Q gets Rs. 30 more than P and R gets Rs. 60 more than Q. The ratio of their share is**- 3 : 2 : 5
- 2 : 5 : 3
- 5 : 3 : 2
- 2 : 3 : 5

Answer : Option D.

Q = P + 30 ⇒ Q – P = 30 and R – Q = 60 = 2 × 30

⇒Required ratio = 2 : 3 : 5

Look : 3 – 2 = 1, 5 – 3 = 2