Cost price of each of the articles A and B is Rs. X. Article A was sold at a profit of 10% and article B was sold at a profit of 30%. If the overall profit earned after selling both the articles is Rs. 136/-, what is the value of 'X'?
Rs 340
Rs 300
Rs 360
Rs 380
Rs 320
Answer : Option A.
Given : 0.1x + 0.3x = 136 => x = 340
Population of a village increased by 5% from 2007 to 2008 and by 25% from 2005 to 2009. If the population of the village was 480 in 2007, what was its population in 2009?
640
610
630
620
650
Answer : Option C.
Population in 2007 = 480
In 2008 = 1.05 × 480 = 504
In 2009 = 1.25 × 504 = 630
400 + 206 × 12 = x
2800
6666
4666
2400
2872
Answer : Option E.
400 + 206 × 12 = x
=> x = 400 + 2472 = 2872
430% of 25 + 75% of 430 = ?
340
860
516
86
630
Answer : Option A.
430% of 25 + 75% of 430 = x 430/100 ( 25 + 75 ) => x = 430
There is a natural number which becomes equal to the square of a natural number when 100 is added to it, and to the square of another natural number when 168 is added to it. Find the number.
189
69
156
224
None of these
Answer : Option C.
Try by options. 3rd option is correct because 100 + 156 = 256 (square of 16) and 168 + 156 = 324 (square of 18).
No other option is satisfying the 2nd condition.
In a rectangular auditorium, chairs are arranged in rows and columns. The number of chairs in each column is more than the number of chairs in each row by 5. If there are in all 300 chairs, find the number of chairs in each row and in each column.
25,20
30,10
23,18
25,12
None of these
Answer : Option D.
Go by options. When there were 300 chairs, so product of chairs in rows and chairs in columns should be 300. Difference of 5 should be there between the seats in rows and columns. So no option out of 1st 3 is satisfying the conditions. So answer is 4th option and correct values are 20 and 15.
A person sets to cover a distance of 12 km in 45 minutes. If he covers of the distance in of time, then what is the speed in the remaining time?
16 km/hr
8 km/hr
12 km/hr
55 km/hr
10 km/hr
Answer : Option C.
Distance already covered = = 9 km, Time spent = min = 30 min Distance left = (12 – 9) km = 3 km, Time left = (45 – 30) min = 15 min ∴ Required speed = 3/(5/16) km/hr = 12 km/hr.
If a train 110 metres in length passes a man walking at the rate of 6 km/hr against it in 6 seconds, It will pass another man walking at the same speed in the same direction in time of
9 1/3sec
10 2/3sec
8 sec
6 sec
7 1/3 sec
Answer : Option E.
Let the speed of the train = x km/hr. Relative speed = (x + 6) km/hr = (x + 6)* 5/18 m/sec. ∴ (x + 6) * 5/18 * 6 = 110 ∴x = 60. ∴ Speed of train = 60 km/hr for 2nd person, Relative speed = (60 – 6) km/hr = 54 * 5/18 m/sec = 15 m/hr.∴Time taken to cross 2nd person = 110/15 = 22/3 = 7 1/3 sec.
The number of ways in which letters of the word PRAISE be arranged
720
610
360
210
None of these
Answer : Option A.
Reqd. number of ways = 6! = 720.
