**How many words, with or without meaning can be formed with the letters of the word MANAGEMENT?**- 226800
- 453600
- 3907200
- 1814400
- 3628800

Answer : Option A.

Reqd. number of ways = (10!/2!2!2!2!)=226800**The number of ways in which letters of the word PRAISE be arranged**- 720
- 610
- 360
- 210
- None of these

Answer : Option A.

Reqd. number of ways = 6! = 720.

**Jar A has 60 litres of mixture of milk and water in the respective ratio of 2: 1. Jar B which had 40 litres of mixture of milk and water was emptied into Jar A, as a result in Jar A, the respective ratio of milk and water becomes 13 : 7. What was the quantity of water in Jar B?**- 8 litres
- 15 litres
- 22 litres
- 7 litres
- 1 litres

Answer : Option B.

Jar A has 60 Litres.

Ratio between milk and water 2:1,

Quantity of Milk in Jar A = 2/3×60 = 40

Quantity of Water in Jar A = 1/3× 60 = 20

40 liters of Mixture B having milk and water is emptied into Jar A.

Therefore, Total Mixture = 60 +40 = 100

The respective Ratio of Milk and Water is 13:7

Quantity of Milk in Jar A = (13/20)×100 = 65

Quantity of Water in Jar A = (7/15)× 100 = 35

Quantity of water in Jar B = 35 – 20 = 15 Litres.**The sum of a series of 5 consecutive odd numbers is 195. The second lowest number of this series is one less than the second highest number of another series of 5 consecutive even numbers. What is 40% of the second lowest number of the series of consecutive even numbers?**- 16.8
- 14.8
- 19.4
- 17.6
- 13.6

Answer : Option E.

The sum of a series of 5 Consecutive odd numbers is 195

Let the Series of Consecutive odd numbers is X, X+2, X+4, X+6, X+8

X+ X+2+ X+4+ X+6+ X+8= 195

5X+20=195

X=35

Series of Consecutive odd numbers is 35, 37, 39, 41, 43

According to the question, the second lowest number of this series is 1 less than the Second highest number of another series of 5 consecutive numbers.

Second lowest number is 37.

Second highest number of another series of 5 consecutive numbers = 37+1 = 38

Therefore, another series of 5 consecutive numbers 32, 34, 36, 38, 40.

40% of the lowest number of the series of consecutive numbers= 34×(4/100) = 13.6**The sum of the dimensions of a room (i.e. length, breadth and height) is 18 metres and its length, breadth and height are in the ratio of 3 : 2 : 1 respectively. If the room is to be painted at the rate of Rs. 15 per m**^{2}, what would be the total cost incurred on painting only the four walls of the room (in Rs.)?- 3250
- 2445
- 1350
- 2210
- 2940

Answer : Option C.

Ratio of length : breadth : height = 3:2:1

Sum of dimensions of room = 18

Length =(3/6) ×18 = 9

Breath =(2/6) ×18 = 6

Height =(1/6) ×18 = 3

Area of four walls = 2h×(l+b) = 2×3(9+6) = 90

Total cost of painting four walls = 90×15 = 1350Mazars Preparation Links- Sample Aptitude Questions of Mazars
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**B is 4/3 times as efficient as A. If A can complete 5/8th of a given task in 15 days, what fraction of the same task would remain incomplete if B works on it independently for 10 days only?**- 3/4
- 2/3
- 5/8
- 4/9
- 2/3

Answer : Option D.

B is 4/3 times as efficient of A.

Ratio of time taken by A and B, A: B is 4:3.

A can complete 5/8^{th}of a given task in 15 days

A can do alone his work in = 8/5×15= 24 days

Therefore, B can do this work= 18

B works independently for 10 days only, thus work done = 10/18 = 5/9

Remaining work (incomplete) = 1-(5/9) = 4/9**In a class, the average weight of boys is 64 kg and that of 75 girls is 70 kg. After a few days, 60% of the girls and 30% of the boys leave. What would be the new average weight of the class (in kg)? Assume that the average weight of the boys and the girls remain constant throughout.**- 63
- 66.5
- 68.5
- 65.5
- Can’t be determined

Answer : Option E.

In this question, number of boys is not mentioned .So, we can’t find new average.**DIRECTIONS for question 8 to 10: What will come in place of question mark (?) in the given number series?****15 27 37 45 51 ?**- 58
- 80
- 65
- 74
- 55

Answer : Option E.

Given series is:

15 27 37 45 51 ?

And the pattern is 27 – 15 = 12, 37 – 27 = 10, 45 – 37 = 8, 51 – 45 = 6.

Thus the next term is 51 + 4 = 55**700 457 376 349 340 ?**- 266
- 329
- 304
- 337
- 307

Answer : Option D.

Given series is:

700 457 376 349 340 ?

Pattern is 700 – 457 = 243, 457 – 376 = 81, 376 – 349 = 27, 349 – 340 = 9

Thus, the next term is 340 – 3 = 337**1 2 6 21 88 ?**- 425
- 475
- 295
- 445
- 395

Answer : Option D.

Given series is:

1 2 6 21 88 ?

Pattern is 1×1+1= 2

2×2+2= 6

6×3+3=21

21×4+4= 88

88×5+5= 445

So the next term of the series is = 445