Sample Aptitude Questions of Mazars-LLP

  1. How many words, with or without meaning can be formed with the letters of the word MANAGEMENT?
    1. 226800
    2. 453600
    3. 3907200
    4. 1814400
    5. 3628800

    Answer : Option A.
    Reqd. number of ways = (10!/2!2!2!2!)=226800
  2. The number of ways in which letters of the word PRAISE be arranged
    1. 720
    2. 610
    3. 360
    4. 210
    5. None of these

    Answer : Option A.
    Reqd. number of ways = 6! = 720.
  1. Jar A has 60 litres of mixture of milk and water in the respective ratio of 2: 1. Jar B which had 40 litres of mixture of milk and water was emptied into Jar A, as a result in Jar A, the respective ratio of milk and water becomes 13 : 7. What was the quantity of water in Jar B?
    1. 8 litres
    2. 15 litres
    3. 22 litres
    4. 7 litres
    5. 1 litres

    Answer : Option B.
    Jar A has 60 Litres.
    Ratio between milk and water 2:1,
    Quantity of Milk in Jar A = 2/3×60 = 40
    Quantity of Water in Jar A = 1/3× 60 = 20
    40 liters of Mixture B having milk and water is emptied into Jar A.
    Therefore, Total Mixture = 60 +40 = 100
    The respective Ratio of Milk and Water is 13:7
    Quantity of Milk in Jar A = (13/20)×100 = 65
    Quantity of Water in Jar A = (7/15)× 100 = 35
    Quantity of water in Jar B = 35 – 20 = 15 Litres.
  2. The sum of a series of 5 consecutive odd numbers is 195. The second lowest number of this series is one less than the second highest number of another series of 5 consecutive even numbers. What is 40% of the second lowest number of the series of consecutive even numbers?
    1. 16.8
    2. 14.8
    3. 19.4
    4. 17.6
    5. 13.6

    Answer : Option E.
    The sum of a series of 5 Consecutive odd numbers is 195
    Let the Series of Consecutive odd numbers is X, X+2, X+4, X+6, X+8
    X+ X+2+ X+4+ X+6+ X+8= 195
    5X+20=195
    X=35
    Series of Consecutive odd numbers is 35, 37, 39, 41, 43
    According to the question, the second lowest number of this series is 1 less than the Second highest number of another series of 5 consecutive numbers.
    Second lowest number is 37.
    Second highest number of another series of 5 consecutive numbers = 37+1 = 38
    Therefore, another series of 5 consecutive numbers 32, 34, 36, 38, 40.
    40% of the lowest number of the series of consecutive numbers= 34×(4/100) = 13.6
  3. The sum of the dimensions of a room (i.e. length, breadth and height) is 18 metres and its length, breadth and height are in the ratio of 3 : 2 : 1 respectively. If the room is to be painted at the rate of Rs. 15 per m2, what would be the total cost incurred on painting only the four walls of the room (in Rs.)?
    1. 3250
    2. 2445
    3. 1350
    4. 2210
    5. 2940

    Answer : Option C.
    Ratio of length : breadth : height = 3:2:1
    Sum of dimensions of room = 18
    Length =(3/6) ×18 = 9
    Breath =(2/6) ×18 = 6
    Height =(1/6) ×18 = 3
    Area of four walls = 2h×(l+b) = 2×3(9+6) = 90
    Total cost of painting four walls = 90×15 = 1350
  4. B is 4/3 times as efficient as A. If A can complete 5/8th of a given task in 15 days, what fraction of the same task would remain incomplete if B works on it independently for 10 days only?
    1. 3/4
    2. 2/3
    3. 5/8
    4. 4/9
    5. 2/3

    Answer : Option D.
    B is 4/3 times as efficient of A.
    Ratio of time taken by A and B, A: B is 4:3.
    A can complete 5/8th of a given task in 15 days
    A can do alone his work in = 8/5×15= 24 days
    Therefore, B can do this work= 18
    B works independently for 10 days only, thus work done = 10/18 = 5/9
    Remaining work (incomplete) = 1-(5/9) = 4/9
  5. In a class, the average weight of boys is 64 kg and that of 75 girls is 70 kg. After a few days, 60% of the girls and 30% of the boys leave. What would be the new average weight of the class (in kg)? Assume that the average weight of the boys and the girls remain constant throughout.
    1. 63
    2. 66.5
    3. 68.5
    4. 65.5
    5. Can’t be determined

    Answer : Option E.
    In this question, number of boys is not mentioned .So, we can’t find new average.
    DIRECTIONS for question 8 to 10: What will come in place of question mark (?) in the given number series?
  6. 15 27 37 45 51 ?
    1. 58
    2. 80
    3. 65
    4. 74
    5. 55

    Answer : Option E.
    Given series is:
    15 27 37 45 51 ?
    And the pattern is 27 – 15 = 12, 37 – 27 = 10, 45 – 37 = 8, 51 – 45 = 6.
    Thus the next term is 51 + 4 = 55
  7. 700 457 376 349 340 ?
    1. 266
    2. 329
    3. 304
    4. 337
    5. 307

    Answer : Option D.
    Given series is:
    700 457 376 349 340 ?
    Pattern is 700 – 457 = 243, 457 – 376 = 81, 376 – 349 = 27, 349 – 340 = 9
    Thus, the next term is 340 – 3 = 337
  8. 1 2 6 21 88 ?
    1. 425
    2. 475
    3. 295
    4. 445
    5. 395

    Answer : Option D.
    Given series is:
    1 2 6 21 88 ?
    Pattern is 1×1+1= 2
    2×2+2= 6
    6×3+3=21
    21×4+4= 88
    88×5+5= 445
    So the next term of the series is = 445

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