# Sample Aptitude Questions of CGI

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1. The retail price of a water geyser is Rs. 1,265. If the manufacturer gains 10 %, the wholesale dealer gains 15 % and the retailer gains 25 %, then the cost of the product is:
1. 800
2. 900
3. 700
4. 600
C.P = 1265*100*100*100/110/115/125
C.P = 800
1. What percent of selling price would be 34 % of cost price if gross profit is 26 % of the selling price?
1. 17.16
2. 74
3. 25.16
4. 88.40
X% of SP = 34% of CP
Also, P = 26% of SP
SP - CP = 0.26(SP)
CP = 0.74(SP)
Now, (34/100)×74
X = 25.16
2. The tax on a commodity is diminished by 10 % and its consumption increased by 10 %. The effect on the revenue derived from it changes by K %. Find the value of K.
1. 1.
2. -2
3. -1
4. 2
Directly using the formula, when a value is increased by R% and then decreased by R%, then net there is ( R∧2)/100 decrease. Putting R = 10, we get 1% decrease.
3. Ratio of Ashok's age to Pradeep's age is 4 : 3. Ashok will be 26 years old after 6 years. How old is Pradeep now?
1. 18
2. 21
3. 15
4. 24
Given A/p= 4/3 Also A = 26 after 6 years, so his present age = 20years, Substituting we get P = 15 years.
4. The incomes of Chanda and Kim are in the ratio 9 : 4 and their expenditures are in the ratio 7 : 3. If each saves Rs. 2,000, then Chanda's expenditure is
1. 60000
2. 80000
3. 70000
4. None of these
Let the incomes of Chanda and Kim be 9x and expenditures be 7y and 3y respectively. Since = Income – Expenditure, we get 9x – 7y = 2000 and 4x – 3y = 2000. Solving, we get, x = 8000 and y = 10000. So Chanda’s expenditure = 7y = 7 × 10000 = Rs. 70,000.
1. A student purchased a computer system and a colour printer. If he sold the computer system at 10 % loss and the colour printer at 20 % gain, he would not lose anything. But if he sells the computer system at 5 % gain and the colour printer at 15 % loss, he would lose Rs. 800 in the bargain. How much did he pay for the colour printer?
1. 8000
2. 16000
3. 9000
4. 533 4
Let C and P be the cost price of Computer and Printer respectively.
So CP = C + P, Case I,
SP = 0.9C + 1.2P.
Since he did not lose anything C + P = 0.9C + 1.2P  C = 2P.
Case II, SP = 1.05C + 0.85P
Since there was the loss of Rs. 800
Rs.800 = C + P – 1.05C – 0.85P
 80000 = 15P – 5C
Using equation from Case I, we get P = Rs.16000.
2. X and Y entered into partnership with Rs. 700 and Rs. 600 respectively. After 3 months X withdrew 2/7 of his stock but after 3 months, he puts back 3/5 of what he had withdrawn. The profit at the end of the year is Rs. 726. How much of this should X receive?
1. 336
2. 366
3. 633
4. 663
X’s profit : Y’s profit
= 700 × 3 + 500 × 3 + 620 × 6 : 600 × 12
= 2,100 + 1,500 + 3,720 : 7,200
= 7,320 : 7,200
= 61 : 60
X’s share in the profit = 61/(60+61) × 726 = 366
3. A man sitting in a train travelling at the rate of 50 km/hr observes that it takes 9 sec for a goods train travelling in the opposite direction to pass him. If the goods train is 187.5 m long, find its speed.
1. 25
2. 45
3. 35
4. 36
Let required speed be x.
So,187.5/{ (x+50)*5/18} =9
4. A runs 5/3 times as fast as B. If A gives B a start of 80m, how far must the winning post be, so that A and B might reach it at the same time?
1. 200
2. 300
3. 270
4. 160
Ratio of speeds of A : B = 5 : 3, So If A runs 5, B runs 3. So difference in distance = 2. So if difference is 2, winning post is 5m. Hence if difference is 2.5*80, winning post is Hence 1st option.
5. A team of workers was employed by a contractor who undertook to finish 360 pieces of an article in a certain number of days. Making four more pieces per day than was planned, they could complete the job a day ahead of schedule. How many days did they take to complete the job?
1. 8
2. 9
3. 10
4. 12