The average score of a cricketer for 13 matches is 42 runs. If his average score for the first 5 matches is 54, then what was his average score (in runs) for last 8 matches?
37
39
34.5
33.5
37.5
Answer: Option C.
Total Score = Average * Number of matches
Total score of 13 matches = 13 × 42 = 546
Total score of first 5 matches = 5 × 54 = 270
Therefore, total score of last 8 matches = 546 – 270 = 276
Average = 276/8 = 34.5
Hence the answer is option C
Simple interest on a sum of money for 4 years at 7 p.c.p.a is Rs. 3584/-. What would be the compound interest (compounded annually) on the same amount of money for 2 years at 4p.c.p.a?
Rs. 1,162.32
Rs. 1,098.72
Rs. 992.38
Rs. 1,231.76
Rs. 1,044.48
Answer: Option E.
Let P be the sum
Therefore,
3584 = (P * 7 * 4) / 100 => P = 12800/-
CI = 12800(1 + (4/100))2 - 12800
=> 13844.48 - 12800 = 1044.48/-
Hence the answer is option E
6*136/8+132 / 628/16-26.25=?
15
24
18
12
28
Answer: Option C.
6*136/8+132 / 628/16-26.25
⇒ 234/13=18 Hence the answer is option C.
(1331)1/3/ 275 *52 = ?
2
4
1
2.5
3
Answer: Option C.
? = (1331)1/3/275 *(5)2
= (113)1/3 / 11*25 *(25)
=1 Hence the answer is option C.
(43)2 + 841 = (?)2 + 1465
41
35
38
33
30
Answer: Option B.
Using BODMAS
(?)2 = (43)2 + 841 – 1465
= 1849 + 841 – 1465 = 1225
Therefore, ? = √1225 = 35
Hence the answer is option B
Answer: Option B.
? = (1097.63 + 2197.36 - 2607.24) ÷ 3.5 = 687.75 ÷ 3.5
= 196.5
Hence answer is option B
A certain number of capsules were purchased for Rs. 216/-. 15 more capsules could have been purchased in the same amount if each capsule was cheaper by Rs. 10/-. What was the number of capsules purchased?
6
14
8
12
9
Answer: Option D
Let x be the cost of each capsule and y be the no of capsules
Therefore, x = 216/y and x - 10 = 216/(y+15)
Putting the value of x from eq. 1 into eq. 2, we get
216/y - 216/(y+15) = 10
y2 +15y - 324 = 0
Solving for y, we get y = 12
Hence answer is option D.
What will come in place of question mark (?)in the given question?
4 6 34 ? 504 1234
194
160
186
156
172
Answer: Option B
Here the difference between each term is in the form of 13+1, 33+1, 53+1, 73+1 and so on
4 6 34 160 504 1234
+2 +28 +126 +344 +730
13 + 1 33 + 1 53 + 1 73 + 1 93 + 1
So ? = 160
Hence answer is option B
A and B are two numbers. 6 times square of B is 540 more than the square of A. if the respective ratio between A and B is 3:2. What is the value of B?
10
12
16
8
14
Answer: Option B.
We are given that
6B2 = A2 + 540 and A : B = 3 : 2
Put the value of A from 2nd equation into the first equation, we get
6B2 = (1.5B)2 + 540
→ (6 – 2.25)B2 = 540 → 3.75B2 = 540 → B2 = 144 → B = 12
Hence answer is option B.
