Dell Aptitude Questions | Aptitude Test For Dell

The list price of an article is Rs. 160 and a customer buys it for Rs. 122.40 after two successive discounts. If the first discount is 10%, then second discount is
1. 12%
2. 10%
3. 14%
4. 15%
Answer: Option D.
SP after a discount of 10%
= (160*90) / 100 = Rs. 144
Second discount
= 144 – 122.40 = Rs. 21.6
If the second discount be x% then

In a school, 10% of number of girls is equal to 1/20 of number of boys. Ratio between the 'number of boys to number of girls is
1. 1:2
2. 2:1
3. 1:4
4. 4:1
Answer: Option B.
LIf boys = x and girls = y, then
The ratio of 25^2.5 : 5³ is same as
1. 5 : 3
2. 5 : 6
3. 1 : 25
4. 25 : 1
Answer: Option D.
25^2.5 : 5³ = (5²)^2.5 : 5³
= 5⁵ : 5³ = 5² : 1 = 25 : 1
If a, b, c, d, e are five consecutive odd numbers, their average is
1. 5(a + 4)
2. abde/5
3. 5(a + b + c + d + e)
4. a + 4
Answer: Option D.
b = a + 2
c = b + 2 = a + 4
d = c + 2 = a + 6
e = d + 2 = a + 8
Therefore, Required average = (a + a + 2 + a + 4 + a + 6 + a + 8)/5
= a + 4
The average of 20 numbers is 15 and the average of first five is 12. The average of the rest is
1. 16
2. 15
3. 14
4. 13
Answer: Option A.
If the average of remaining numbers be x, then
20 × 15 = 5 × 12 + 15x
⇒ 300 = 60 + 15x
⇒ 15x = 300 – 60 = 240
=> x = 240/15 = 16
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A tradesman sold an article at a loss of 20%. If the selling price had been increased by Rs. 100, there would have been a gain of 5%. The cost price of the article (in Rs.) was
1. 100
2. 200
3. 400
4. 500
Answer: Option C.
C. P. of article = Rs. X
∴ First SP = 80x/100 = Rs. 4x/5
Case II

⇒ 5x = 2000 ⇒ x = 2000/5 = Rs. 400
The price of an article is first decreased by20% and then increased by 30%. If the resulting price is Rs. 416, the original price of the article is
1. Rs. 350
2. Rs. 405
3. Rs. 400
4. Rs. 450
Answer: Option C.
If the original price of article be Rs. X, then
A man performs 2/15 of the total journey by train 9/20 by bus and the remaining 10 km on foot. His total journey in km is
1. 15.6
2. 24
3. 16.4
4. 12.8
Answer: Option B
If the total journey be x km, then
2x/15+9x/20+10=x
=>x-2x/15-9x/20=10
=> 60x-8x-27x/60=10
=> 25x/60=10
=> X=60*10/25=24km
By walking at 3/4 of his usual speed, a man reaches his office 20 minutes later than usual. His usual time is
1. 30 min
2. 75 min
3. 90 min.
4. 60 min.
Answer: Option D.
New speed = 3/4 × usual speed
∴ New time = 4/3 × usual time.
∴ 1/3 × usual time = 20 minutes
⇒ Usual time = 3 × 20
= 60 minutes
If the compound interest on a certain sum for two years at 12% per annum is Rs. 2544 the simple interest on it at the same rate for 2 years will be
1. Rs. 2400
2. Rs. 2500
3. Rs. 2480
4. Rs. 2440
Answer: Option A.