Aptitude questions form a part of the game-based section of Capgemini written test. These are based on the basic mathematical and reasoning concepts of puzzles, arithmetic operations, grids, etc. Aptitude section is a mix of moderate and slightly difficult questions. Here, we have given certain questions on fundamental topics, that will help you prepare for Capgemini aptitude test:

**A 30% loss on cost price is what percent loss on selling price?**- 30%
- 20%
- 15%
- None of these

Answer: Option D

Let CP = 100 ; SP=70

Loss= 30/70 × 100 = 42.85%**A, B and C hire a taxi for Rs. 2400 for one day. A, B and C used the car for 6 hours, 8 hours and 10 hours respectively. How much did C pay?**- Rs. 800
- Rs. 1000
- Rs. 600
- Rs. 1200

Answer: Option B

Let total fair be = 2400 ;

Therefore c share =10/24 × 2400 = 1000

**The ratio of investments of A and B is 8 : 7 and the ratio of their yearend profits is 20 : 21. If B invested for 12 months, then find the period of investment of A:**- 6 months
- 8 months
- 10 months
- 12 months

Answer: Option C

Let A invest for x months ; A = 8x months,

B = 7 × 12 = 84 months

8x/84 = 20/21

⇒ x = 10

**What percent is 2 minutes 24 seconds of an hour?**- 6%
- 2%
- 4%
- 8%

Answer: Option C

%=144/60×60 = 4%**Evaluate: 3 cos 80° cosec 10° + 2 cos 59° cosec 31°**- 1
- 3
- 2
- 5

Answer: Option D

3 cos 80°. Cosec 10° + 2 cos 59° . cosec 31°

= 3 cos (90° - 10°). Cosec 10° + 2 cos (90° - 31°).Cosec 31°

=3sin10°.Cosec10° +2sin31°.cosec31°

=3+2=5

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**The total cost of 8 buckets and 5 mugs is Rs. 92 and the total cost of 5 buckets and 8 mugs is Rs. 77. Find the cost of 2 mugs and 3 buckets.**- Rs. 35
- Rs. 70
- Rs. 30
- Rs. 38

Answer: Option A

CP of 1 bucket = Rs. X

CP of 1 mug = Rs. Y

∴ 8x + 5y = 92....... (i)

5x + 8y = 77........(ii)

By equation (i) × 5 – equation (ii) × 8.

40x + 25y – 40x – 64y

= 460 – 616 ⇒ − 39y = - 156⇒ y = 4

From equation (i),

8x + 20 = 92 ⇒8x = 92 – 20 = 72 ⇒ x = 9

∴ CP of 2 mugs and 3 buckets

= 2 × 4 + 3 × 9 = 8 + 27 = Rs. 35**If 4x/3 + 2P = 12 for what value of P, x = 6?**- 6
- 4
- 2
- 1

Answer: Option C

When x = 6, (4 * 6)/3 + 2P = 12

⇒ 8 + 2P = 12

⇒ 2P = 12 – 8 = 4

⇒ P = 2**What number must be added to the expression 16a**^{2}– 12a to make it a perfect square?- 9/4
- 11/2
- 13/2
- 16

Answer: Option A

a^{2}- 2ab + b^{2}= (a-b)^{2}

∴ 16a^{2}– 12a = (4a)^{2}- 2*4a*3/2

Hence, on adding (3/2)^{2}= 9/4, expression will be a perfect square.**The straight line 2x + 3y = 12 passes through:**- 1st, 2nd and 3rd quadrant
- 1st, 2nd and 4th quadrant
- 2nd, 3rd and 4th quadrant
- 1st, 3rd and 4th quadrant

Answer: Option B

The usual way to solve these type of questions is to put x = 0 once and find y coordinate. This would represent the point where the line cuts the Y axis.

Similarly put y = 0 once and find x coordinate. This would represent the point where the line cuts the X axis. Then join these points and you will get the graph of the line.

So when we put x = 0 we get y = 4.

When we put y = 0 we get x = 6.

So when we join these points we see that we get a line in 1st quadrant, which when extended both sides would go to 4th and 2nd quadrants. So option B.**In ΔABC, ∠A + ∠B = 65°, ∠B + ∠C = 140°, then find ∠B.**- 40°
- 25°
- 35°
- 20°

Answer: Option B

∠A + ∠B = 65°

∴ ∠C = 180° - 65° = 115°

∠B + ∠C = 140°

∴ ∠B = 140° - 115° = 25°