**Mr Katial buys a house for Rs. 1,00,000 and rents it. He puts 12.5 % of each month’s rent aside for upkeep and repairs, pays Rs. 325 per year as taxes and realizes 5.5 % annually on his purchase price. The monthly rent is -**- Rs. 554.76
- Rs. 634.76
- Rs. 654.76
- None of these

Answer : Option A.

Return on purchase price = 5.5% of 1,00,000 = 5500.

Amount including taxes = 5500 + 325 = 5825. Therefore amount to be received as a rent

= 5825 * 100/87.5 = 6657.14. Now, monthly rental = 6657.14/12 = Rs. 554.76**A batsman has a certain average of runs for 12 innings. In the 13th inning he scores 96 runs thereby increasing his average by 5 runs. What is his average after the 13th inning?**- 64
- 48
- 36
- 72

Answer : Option C.

Let its average after 12 innings be A.

Therefore, after 13th inning its average becomes A + 5.

Now, A + 5 = (12A + 96)/13 => A = 31.

So its present average = 31 + 5 = 36.**What should be subtracted from 15, 28, 20 and 38 so that the remaining numbers may be proportional?**- 4
- 2
- 6
- None of these

Answer : Option B.

Let the number to be subtracted = x.

Therefore, (15-x)/(28-x) = (20-x)/(38-x) => x = 2.**A and B enter into a partnership with Rs. 50,000 and Rs. 60,000 respectively. C joins them after x months contributing Rs. 70,000 and B leaves x months before the end of the year. If they share the profit in the ratio of 20 : 18 : 21, then the value of x is**- 3
- 9
- 6
- 8

Answer : Option A.

Investment of A = 50,000 × 12.

Investment of B = 60,000 × (12 – x).

Investment of C = 70,000 × (12 – x).

Therefore, ratio of investment = A : B : C = [50,000 × 12] : [60,000 × (12 – x)] :

[70,000 × (12 – x)] = 20 : 18 : 21**A cash payment that will settle a bill for 250 chairs at Rs. 50 per chair less 20 % and 15 % with a further discount of 5 % on cash payment is**- Rs. 8,075
- Rs. 7,025
- Rs. 8,500
- None of these

Answer : Option A.

Calculating single equivalent discount

= -20 - 15 + (20*15)/100

= -32 and -32 - 5 + (32*5)/100 = -35.4

Therefore we had to give total of 35.4% discount. Therefore cash payment

= 64.6% of (250 × 50) = Rs. 8075.HAL Preparation Links- Sample Aptitude Questions of HAL
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**Eight children and 12 men complete a certain piece of work in 9 days. If each child takes twice the time taken by a man to finish the work, in how many days will 12 men finish the same work?**- 15
- 8
- 9
- 12

Answer : Option D.

(8C + 12M) × 9 days = 12M × D days……. (i). Also C = M/2, putting this in (i), we get D = 12 days.**Two pipes P and Q would fill a cistern in 24 and 32 minutes, respectively. Both pipes are kept open. When should the first pipe be turned off so that the cistern may be just filled in 16 minutes?**- After 10 minutes
- After 12 minutes
- After 14 minutes
- None of these

Answer : Option B.

Pipe P’s one min work = 1/24 and pipe Q’s one min work = 1/32.

As the cistern is to be filled in 16 min, therefore the pipe Q will work for 16 min.

Now pipe Q will complete 1/32 * 16 = 1/2 of the work, rest of the half work will be completed by pipe P in 1/2 * 24 = 12 min.

Hence pipe P should be turned off after 12 minutes.**Two trains, 130 m and 110 m long, are going in the same direction. The faster train takes one minute to pass the other completely. If they are moving in opposite directions, they pass each other completely in 3 seconds. Find the speed of each train.**- 38 m/sec, 36 m/sec
- 42 m/sec, 38 m/sec
- 36 m/sec, 42 m/sec
- None of these

Answer : Option B.

Let the speed of the faster train = S and speed of the slower train = s.

When they are moving in same direction,

(S – s) × 60 = 130 + 110 ⇒ S – s = 4……..(i)

When they are moving in the opposite direction, (S + s) × 3 = 130 + 110

⇒ S – s = 80…….(ii)

Solving (i) and (ii),

we get S = 42 m/sec and s = 38 m/sec.**A man swimming in a stream which flows 1**^{1}⁄_{1}km/hr finds that in a given time he can swim twice as far with the stream as he can against it. At what rate does he swim?- 5
^{1}⁄_{1}km/hr - 4
^{1}⁄_{1}km/hr - 7
^{1}⁄_{1}km/hr - None of these

Answer : Option B.

Let the speed of man = M and speed of water, W = 3/2 km/hr. According to the given condition,

Speed downstream = 2 × Speed upstream- 5
**A trader has 50 kg of rice, a part of which he sells at 10 % profit and the rest at 5 % loss. He gains 7 % on the whole. How much was sold at 10 % gain and how much was sold at 5 % loss?:**- 40 kg, 15 kg
- 30 kg, 10 kg
- 35 kg, 40 kg
- 40 kg, 10 kg

Answer : Option D.

It can be done by option also as only in the 4th option sum of two quantities is 50 kg.

Alternative method, we can use alligations

As solved rice has to be divided in the ratio 4 : 1.

So rice sold at 10% profit = 40 kg and rice sold at 5% loss = 10 kg.