This section is not present in this company's placement process. If you still want to practise, some questions are provided below.
DIRECTIONS for the question 1-5: Read the information given below and Answer & Explanation the questions given after that. A researcher studying organic compounds has found that five different molecules- T, W, X, Y, and Z from chains according to the following rules.
A chain consists of three or more molecules, though the molecules in the chain are not necessarily different.
T is never found on either end of a chain.
If W appears in a chain, it appears more than once.
X is never found next to Y in a chain.
W is never found on the end of chain unless Z is found somewhere in the chain.
If Y appears in a chain, Z appears also.
Which of the following is a possible chain of molecules?
T, X, Y, Z
Y, T, X, X
W, Z, T, Y
W, W, X ,Z
Answer : Option D.
Option A is rejected as T can never be at the end. Option B is rejected as if Y is there, Z should also be there. option C is also rejected,as if Y is there, Z should also be there. Option D satisfies all the conditions.
In the chain - W W Z which of the following would be substituted for the dash to make a chain?
Z
W
T
I only
II only
I and II only
I. II. and III
Answer : Option C.
Z and W can be substituted for the dash to make a chain.
Which of the following is not a chain but could be turned into a chain by changing the order of the molecules?
X, Y, T, X
W, X, X, W
T, X, X, Y
W ,T ,T ,W
Answer : Option B.
Option A and C are rejected because with Y, Z should be there.Option D is rejected as W cannot be at end until Z is there. Only option B satisfies all the conditions.
Which of the following could be turned into a chain by replacing the dash with a molecule?
W W - Y T X
W X T Y - Y
X - X Y T Y
- X X T W Y
Answer : Option A.
Option Band D are rejected because with Y, Z should be there and If W appears in a chain, it appears more than once. So in single space we cannot place two molecules.Option C is rejected as X is never found next to Y in a chain.Only option A option can be turned into a chain by introducing Z.
Which of the following sequences can be converted into a chain by adding Z and rearranging the molecules?
X, Y ,X ,T
W, T, T, Z
X, X, Y, W
I only
II only
III only
I and III only
Answer : Option A.
II. W, T, T, Z can not be converted into a chain by adding Z and rearranging the molecules as If W appears in a chain, it appears more than once.
III. X, X, Y, W can not be converted into a chain by adding Z and rearranging the molecules as X is never found next to Y in a chain.
Hence only III. X, X, Y, W can not be converted into a chain by adding Z and rearranging the molecules
DIRECTIONS for the question 6-10: Answer & Explanation the following questions as per the best of your ability.
JLN : SQO :: PRT : ?
UYW
UTV
YWU
VUT
Answer : Option C.
In first alphabet, there is a difference of 9 [J(10) and S(19)].
In 2nd alphabet, there is a difference of 5[L(12) and Q(17)].
In 3rd alphabet, there is a difference of 1 [N(14) and O(15)].
Same pattern occurs in PRT. Thus, Answer is C.
Find the odd man out.
February
April
June
August
Answer : Option A.
February has variable number of days
If SKEW is coded as POCY, then for what word do the letters JYQV stand?
MSUT
MUTS
SUTM
MUST
Answer : Option D.
S K E W - P O C Y
In first alphabet, there is decrease of 2 alphabets, same occurs in M to J. In third alphabet, there is decrease of 1 alphabet. This makes option D as Answer.
Vijay starts walking straight forward east. After walking 75 meters, he turns to the left and walks 25 meters straight. Again he turns to the left and walks a distance of 40 meters straight. Again he turns to the left and walks a distance of 25 meters. How far is he from the starting point?
140 meters
50 meters
35 meters
115 meters
Answer : Option C. Distance is of 35 metres. Hence C option.
Distance is of 35 metres. Hence C option.
