Water is flowing at the rate of 3 km/hr through a circular pipe of 20 cm internal diameter into a circular cistern of diameter 10m and depth 2m. In how much time will the cistern be filled?
l hour
1 hour 40 minutes
1 hour 20 minutes
2 hours 40 minutes
Answer: Option B.
Water flowed in 1 hour through the pipe
=22/7 * 10*10*3000/10000 meter3
=660/7 meter3
Volume of circular/cylindrical cistern
=660/7 * 5*5*2 = 1100/7 meter3
= Required Time = 1100/7/660/7 = 5/3 hours
= 1 hour 2/3 * 60 minutes
= 1 hour 40 minutes
A bicycle wheel makes 5000 revolutions in moving 11 km. The diameter of the wheel, in cm, is
35
55
65
70
Answer: Option D.
Distance covered by wheel in one revolution = 2Πr
∴ 5000 × 2Πr = 11 × 1000
⇒ 5000 × 2 × 22/7 × r = 11000
⇒ r =11000*7 / 5000*2*22 = 0.35 metre
= 35 cm
∴ Diameter
= 2 × radius = 2 × 35 = 70 cm
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At each corner of a triangular field of sides 26 m, 28 m and 30 m, a cow is tethered by a rope of, length 7 m. The area (in m2) ungrazed by the cows is
336
259
154
77
Answer: Option C.
Area grazed by all cows 180° / 360 ° Π r 2 = Π r2 = 1/2 * 22/7 *7*7 = 77 sq.metre Semi-perimeter of triangular field(s)
= 26+28+30 / 2 = 42 metre
∴ Area of the field
√s(s-a)(s-b)(s-c)
√42(42-26)(42-28)(42-30)
√42*16*14*12
= 336 sq. metre
∴ Area ungrazed by the cows = 336 - 77 = 259 sq. metre
A shopkeeper allows 23% commission on his advertised price and still makes a profit of 10%. If he gains Rs. 56 on one item, his advertised price of the item, in Rs., is
820
780
790
800
Answer: Option D.
Let the advertised price be Rs. x. ∴ S.P. = Rs. 77x/100
∴ C.P. = Rs(77x/100 - 56)
⇒ 77x -5600/100 =(100/110 * 77x/100)
⇒77x -5600/100 = 7x/10
⇒ 7x -5600 = 70x ⇒ 7x = 5600 ⇒ x = Rs. 800
The average of 25 observations is 13. It was later found that an observation 73 was wrongly entered as 48. The new average is
12.6
14
15
13.8
Answer: Option B.
Difference of two observations = 73 - 48 = 25
∴ New average = 13 + 25/25 = 14
If the cost price of 10 articles is equal to the selling price of 8 ar¬ticles, then gain per cent is
10%
8%
50%
25%
Answer: Option D.
Profit percent= 10-8/8 × 100 = 25%
An article is marked 40% above the cost price and a discount of 30% is allowed. What is the gain or loss percentage?
10% gain
5% gain
2% loss
12% loss
Answer: Option D.
Let the C.P. of article be Rs. 100. ∴ Marked price = Rs. 140 S.P. = 70% of 140 = Rs. 98
A man bought oranges at the rate of 8 for Rs. 34 and sold them at the rate of 12 for Rs. 57. How many oranges should be sold to earn a net profit of Rs. 45?
90
100
135
150
Answer: Option A
Let the man buy 24 (LCM of 8 and 12) oranges. ∴ C.P. of 24 oranges = 34/8 × 24 = Rs. 102 S.P. of 24 oranges = 57/12 × 24 = Rs. 114 Gain= 114- 102 = Rs. 12 ∵ Rs. 12≡ 24 oranges ∴ Rs. 45 ≡ 24/12 × 45 = 90 oranges
The number 0.121212.... in the form p/q is equal to
4/11
2/11
4/33
2/33
Answer: Option C.
0.121212 …. = 0.12 = 12/99 =4/33
