The simple interest on Rs. 4000 in 3 years at the rate of x% per annum equals the simple interest on Rs. 5000 at the rate of 12% per annum in 2 years. The value of x is
8%
9%
10%
6%
Answer: Option C.
S.I = Principal*Time*Rate/100
Therefore 4000*3**/100 = 5000*2*12/100 => * 5*2*12/4*3
=10% per annum
If x2 – 3x + 1 = 0, then the value of x2 + x + 1/x + 1/x2 is
A number x when divided by 289 leaves 18 as a remainder. The same number when divided by 17 leaves y as a remainder. The value of y is
3
1
5
2
Answer: Option B.
Here, the first divisor (289) is a multiple of second divisor (17)
∴ Required remainder = Remainder obtained on dividing 18 by 17 = 1. Hence the answer is option 2.
An equation of the form ax + by + c = 0 where a ≠ 0, b ≠ 0, c = 0 represents a straight line which passes through
(0, 0)
(3, 2)
(2, 4)
None of these
Answer: Option A.
Ax+by+c = 0
When c = 0
ax+by = 0
by = -ax ⇒ y = - ax/b
when x = 0, y = 0 i.e., this line passes through the origin (0,0).
The numerator of a fraction is 4 less than its denominator. If the numerator is decreased by 2 and the denominator is increased by 1, then the denominator becomes eight times the numerator. Find the fraction.
-4/8
2/7
3/8
3/7
Answer: Option D
Original fraction = (x - 4)/x
In case II,
8(x - 4 - 2) = x + 1
⇒ 8x - 48 = x + 1
⇒ 7x = 49 ⇒ x = 7
∴Original fraction
= (7 - 4)/7 = 3/7
If x2 = y + z, y2 = z + x and z2 = x + y then the value of 1/(1+x) + 1/(1+y) + 1/(1+z) is
2
0
-1
1
Answer: Option D.
In a triangle ABC, ∠A = 90°, ∠C = 55°, AD bar ⊥ BC bar. What is the value of ∠BAD?
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